gitlab ci工作流程规则

问题描述 投票:0回答:1

下面来自 gitlab 的示例正在运行,而我的代码却无法运行。我正在使用类似的逻辑。请推荐。

Gitlab 代码 -

variables:
  PROJECT1_PIPELINE_NAME: 'Default pipeline name'  # A default is not required.

workflow:
  name: '$PROJECT1_PIPELINE_NAME'
  rules:
    - if: '$CI_PIPELINE_SOURCE == "merge_request_event"'
      variables:
        PROJECT1_PIPELINE_NAME: 'MR pipeline: $CI_MERGE_REQUEST_SOURCE_BRANCH_NAME'
    - if: '$CI_MERGE_REQUEST_LABELS =~ /pipeline:run-in-ruby3/'
      variables:
        PROJECT1_PIPELINE_NAME: 'Ruby 3 pipeline'
    - when: always  # Other pipelines can run, but use the default name

我的代码-

variables:
  PIPELINE_NAME: "default"
workflow:
  name: '$PIPELINE_NAME'
  rules:
    - if: '$APPLICATION_ID == ""'
      variables:
        PIPELINE_NAME: '$ACCESS_TYPE-$ROLE_DEFINATION-$GITLAB_USER_EMAIL'
    - if: '$APPLICATION_ID'
      variables:
        PIPELINE_NAME: '$ACCESS_TYPE-$APPLICATION_ID-$GITLAB_USER_EMAIL'
gitlab yaml gitlab-ci
1个回答
0
投票

出现错误。管道名称未显示的问题是因为我使用了 gitlab 变量 - PIPELINE_NAME

我更改了代码以使用PROJECT1_PIPELINE_NAME。它起作用了。

workflow:
  name: '$PROJECT1_PIPELINE_NAME'
  rules:
    - if: '$APPLICATION_ID == ""'
      variables:
        PROJECT1_PIPELINE_NAME: '$ACCESS_TYPE-$ROLE_DEFINATION-$GITLAB_USER_EMAIL'
    - if: '$APPLICATION_ID'
      variables:
        PROJECT1_PIPELINE_NAME: '$ACCESS_TYPE-$APPLICATION_ID-$GITLAB_USER_EMAIL'
© www.soinside.com 2019 - 2024. All rights reserved.