TCP客户端如何连接服务器并发送到服务器端?出现错误并且无法成功运行代码。

问题描述 投票:0回答:3

我正在学习 TCP,并正在尝试客户端/服务器程序。我的服务器端正在工作,但在我的客户端,我无法成功连接到服务器端。

我的客户端的错误代码

第一个错误:

回溯(最近一次调用最后一次): 文件“tcpclient.py”,第 13 行,位于 clientSocket.connect((服务器名称, 服务器端口)) 类型错误:需要 str、bytes 或 bytearray,而不是列表

第二个错误:

回溯(最近一次调用最后一次): 文件“tcpclient.py”,第 34 行,位于 clientSocket.send(clientSentence.encode(), serverAddress) 类型错误:需要一个整数(获取类型元组)

服务器代码:此代码运行成功。

import sys
from socket import*

serverSocket = socket(AF_INET, SOCK_STREAM)
serversys = sys.argv

if len(serversys) == 1: 
    serverPort = 9999
else:
    serverPort = serversys[1]
    serverPort = int(serverPort)

serverSocket.bind(('', serverPort)) 
serverSocket.listen(1)
print ("The server is ready to receive.")

while True:
    connectionSocket, addr = serverSocket.accept()
    print ("Connection accepted from: ", addr)

    clientSentence = connectionSocket.recv(1024).decode()


    clientSentence, clientAddress = serverSockset.recv(1024)
    clientSentence.decode()
    connectionSocket.close()

    if clientSentence[0].decode() == 'U':
        serverSentence = clientSentence.upper()
        connectionSocket.send(serverSentence[1:].encode(), clientAddress)
        connectionSocket.close()
    elif clientSentence[0].decode() == 'L':
        serverSentence = clientSentence.lower()
        connectionSocket.send(serverSentence[1:].encode(), clientAddress)
        connectionSocket.close()
    elif clientSentence[0].decode() == 'I':
        serverSentence = clientSentence.title()          
        connectionSocket.send(serverSentence[1:].encode(), clientAddress)
        connectionSocket.close()

Client:这是两个错误发生的地方。

import sys
from socket import*

clientSocket = socket(AF_INET, SOCK_STREAM)

clientsys = sys.argv
serverName = clientsys[1:]
serverPort = clientsys[2:]

clientSocket.connect((serverName, serverPort)) #First Error

serverPort = [int(serverPort) for serverPort in serverPort]
serverAddress = (serverName, serverPort)

sentenceChoice = input("Enter U for UPPERCASE SENTENCE, L for lowercase sentence, \nor I for Initial Caps Sentence: ")
sentence = input("Enter sentence: ")

clientSentence = sentenceChoice+sentence

clientSocket.send(clientSentence.encode(), serverAddress) #Second Error
serverSentence = clientSocket.recv(1024)
print('From Server: ', serverSentence.decode())
clientSocket.close()
python sockets
3个回答
1
投票

您的第一个错误是由于您使用列表切片作为服务器名称和端口引起的。改成这样:

serverName = clientsys[1]
serverPort = clientsys[2]

您的第二个错误是因为

socket.send()
不接受
serverAddress
元组参数(您在哪里想到
socket.sendto()
?无论哪种方式,您都可以通过简单地删除参数来修复:

clientSocket.send(clientSentence.encode())

链接到

socket.send
文档:https://docs.python.org/3/library/socket.html#socket.socket.send


1
投票

您确定它应该是 clientsys[2:] 而不是 clientsys[2] 吗?


1
投票

发生错误的原因是您正在使用列表切片来查找服务器和端口

sys.argv
:

clientsys[1:]
clientsys[2:]

列表切片操作的结果始终是列表:

l = [1, 2, 3]
>>>l[1:]
[2, 3]
>>>print(l[2:])
>>>[3]

相反,使用索引:

serverName = clientsys[0]
serverPort = clientsys[1]
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