我有一个非常大的js React项目我想搜索项目中的一些特定单词，但有2400个单词

Question

我有一个非常大的js React项目，我想搜索项目中的一些特定单词，但有2400个单词，所以我无法使用vsc的ctrl shift搜索我需要一个插件或程序，它需要2400个单词作为输入，然后搜索整个项目并告诉 x 这个词在这个项目中使用了 5 次。我尝试了这个程序，它不起作用

import os

def search_text_in_directory(directory, text_to_search):
    total_occurrences = 0
    
    for root, dirs, files in os.walk(directory):
        for file in files:
            if file.endswith(".js"):
                file_path = os.path.join(root, file)
                with open(file_path, 'r', encoding='utf-8') as f:
                    content = f.read()
                    occurrences = content.count(text_to_search)
                    total_occurrences += occurrences
                    if occurrences > 0:
                        print(f"'{text_to_search}' found in '{file_path}'")
    
    return total_occurrences

directory_to_search = r"C:\Users\hmmer\newsapi-app"  # Your project directory path
text_to_search = "news-image"
total_occurrences = search_text_in_directory(directory_to_search, text_to_search)
print(f"Total occurrences of '{text_to_search}': {total_occurrences}")

Answer 1

我假设您的系统上存在最常见的 UNIX 工具：

cd directory_to_search
grep -oR text_to_search * | wc -l

^- 这将输出出现的次数。

您可以将

i

添加到 grep (

-oRi

) 以进行不区分大小写的匹配。

grep: Searches for patterns etc.
 -o: Prints only the matching part of the lines.
 -R: Recursively search subdirectories listed.  (i.e., force grep to behave as rgrep).
 -i: Perform case insensitive matching.  By default, grep is case sensitive.

wc: Counts words etc.
 -l: The number of lines in each input file is written to the standard output.