动态MVC路由：操作名称

Question

我有一个名为About的控制器和一个名为Index的动作。我希望URL像这样（动作名称将是动态的）：

www.example.com/about/aaa
www.example.com/about/bbb
www.example.com/about/ccc

Routing

routes.MapRoute(
    name: "About",
    url: "{controller}/{name}",
    defaults: new { controller = "About", action = "Index"}

Controller

public class AboutController : Controller
{
    // GET: /About/
    public ActionResult Index(string name)
    {
        return View();
    }
}

查看

@{
    ViewBag.Title = "Index";
}

<h2>Index About</h2>

Answer 1

这应该起作用。

routes.MapRoute(
    name: "About",
    url: "About/{name}",
    defaults: new
    {
        controller = "About",
        action = "Index"
    });

确保您的默认路由存在并且在关于路由之后    

Answer 2

routes.MapRoute(
    name: "About",
    url: "about/{name}/{id}",
    defaults: new { controller = "About", action = "Index", id=UrlParameter.Optional}

Answer 3

您可以将ActionResult名称作为参数传递：

public ActionResult Index(string name)
{
    return View(name);
}    

public ActionResult First()
{
    return View();
}

public ActionResult Second()
{
    return View();
}

在视图中：
@Html.ActionLink("Get Action named Firts" "Index", "Home", new {name = "First"}, null)