如何在服务中获取WindowManager？

Question

我正在尝试将我在Android上找到的Java示例转换为C＃：

[Service]
public class SampleService :Service
{
    public override IBinder OnBind(Intent intent)
    {
        return null;
    }

    public override void OnCreate()
    {
        base.OnCreate();

        // create a windowManager object - relatively easy
        var windowManager = GetSystemService(Context.WindowService).JavaCast<IWindowManager>();

        // create layoutParams based on WindowManager LayoutParams class 
        // (i.e. static member of class that doesn't exist in service context?!?!
        var layoutParams = new WindowManager.LayoutParams(1, 1,
            WindowManager.LayoutParams.TYPE_SYSTEM_OVERLAY,
            WindowManager.LayoutParams.FLAG_WATCH_OUTSIDE_TOUCH,
            PixelFormat.TRANSLUCENT
        );
    }
}

问题是在C＃世界中，WindowManager似乎在服务中不可用，而在Java中它是（至少根据我看到的例子）。

在C＃中，IWindowManager可用，但不包含静态成员。

有办法做到这一点吗？

Answer 1

似乎不是使用WindowManager，而是使用该类

WindowManagerLayoutParams

所以代码：

    LayoutParams layoutParams = new WindowManager.LayoutParams(1, 1,
        WindowManager.LayoutParams.TYPE_SYSTEM_OVERLAY,
        WindowManager.LayoutParams.FLAG_WATCH_OUTSIDE_TOUCH,
        PixelFormat.TRANSLUCENT
    );

变

var layoutParams = new WindowManagerLayoutParams(1, 1, 
    WindowManagerTypes.SystemOverlay, 
    WindowManagerFlags.WatchOutsideTouch, 
    Format.Translucent);