for i in (1..10).to_a do
p "#{i} #{i[0]} #{i[1]}"
end
结果将是:
"1 1 0"
"2 0 1"
"3 1 1"
"4 0 0"
"5 1 0"
"6 0 1"
"7 1 1"
"8 0 0"
"9 1 0"
"10 0 1"
我认为如果数字为偶数,则arr [i] [i]返回0,但似乎在这里可以使用其他逻辑
int [n]→0,1 =>返回int的二进制表示形式中的第n位,其中int [0]是最低有效位。
i[1] i[0]
0 0 0 1 => 1
0 0 1 0 => 2
0 0 1 1 => 3
0 1 0 0 => 4
0 1 0 1 => 5
0 1 1 0 => 6
0 1 1 1 => 7
1 0 0 0 => 8
1 0 0 1 => 9
1 0 1 0 => 10