C中的动态数组push（）导致Valgrind错误

Question

我试图用三个输入参数在C中创建一个函数。动态数组，如果是整数，它的长度和整数。该函数将动态数组的大小增加一个元素，并将整数（参数）作为新元素放在其末尾。有一个非常简单的代码可以使用，但在Valgrind中会产生内存泄漏错误。

#include <stdio.h>
#include <stdlib.h>

void pushINT(int*arr,int*size,int data) {
    int*tmp=realloc(arr,(*size+1)*sizeof(int));
    if(tmp==NULL)exit(100);
    else {
        arr[*size]=data;
        (*size)=*size+1;
    }
}

int main() {
    int* array=malloc(0);
    int arraySIZ=0;

    for(int i=0;i<10;i++) pushINT(array,&arraySIZ,i);
    for(int i=0;i<arraySIZ;i++) printf("%d",array[i]);
    printf("\n");

    free(array);
    return 0;
}

Valgrind输出：

==19581== Memcheck, a memory error detector
==19581== Copyright (C) 2002-2017, and GNU GPL'd, by Julian Seward et al.
==19581== Using Valgrind-3.14.0 and LibVEX; rerun with -h for copyright info
==19581== Command: /home/filip/Documents/b3b36PRG/HW05/main.c
==19581== 
/home/filip/Documents/b3b36PRG/HW05/main.c: line 4: syntax error near unexpected token `('
/home/filip/Documents/b3b36PRG/HW05/main.c: line 4: `void pushINT(int*arr,int*size,int data) {'
==19581== 
==19581== HEAP SUMMARY:
==19581==     in use at exit: 83,410 bytes in 2,151 blocks
==19581==   total heap usage: 3,812 allocs, 1,661 frees, 145,949 bytes allocated
==19581== 
==19581== 109 (32 direct, 77 indirect) bytes in 1 blocks are definitely lost in loss record 619 of 690
==19581==    at 0x483880B: malloc (vg_replace_malloc.c:309)
==19581==    by 0x192341: xmalloc (in /usr/bin/bash)
==19581==    by 0x146EEE: make_bare_simple_command (in /usr/bin/bash)
==19581==    by 0x146FC5: make_simple_command (in /usr/bin/bash)
==19581==    by 0x141C5B: yyparse (in /usr/bin/bash)
==19581==    by 0x1380C9: parse_command (in /usr/bin/bash)
==19581==    by 0x1381D7: read_command (in /usr/bin/bash)
==19581==    by 0x13845F: reader_loop (in /usr/bin/bash)
==19581==    by 0x136B68: main (in /usr/bin/bash)
==19581== 
==19581== LEAK SUMMARY:
==19581==    definitely lost: 32 bytes in 1 blocks
==19581==    indirectly lost: 77 bytes in 5 blocks
==19581==      possibly lost: 0 bytes in 0 blocks
==19581==    still reachable: 83,301 bytes in 2,145 blocks
==19581==         suppressed: 0 bytes in 0 blocks
==19581== Reachable blocks (those to which a pointer was found) are not shown.
==19581== To see them, rerun with: --leak-check=full --show-leak-kinds=all
==19581== 
==19581== For counts of detected and suppressed errors, rerun with: -v
==19581== ERROR SUMMARY: 1 errors from 1 contexts (suppressed: 0 from 0)

是什么导致这个问题？我怀疑realloc（）。

Answer 1

功能应该是：

void pushINT(int **arr,int *size,int data) {
    int *tmp=realloc(*arr,(*size+1)*sizeof(int));
    if (tmp==NULL) exit(100);
    *arr= tmp;
    tmp[*size]=data;
    (*size)=*size+1;
}

请注意，它现在收到一个双指针，并记住realloc可以更改内存位置。因此有必要更新调用者的指针，这就是它需要双指针的原因。

---

Or as Jonathan Leffler suggests:

int *pushINT(int *arr,int *size,int data) {
    int *tmp=realloc(arr,(*size+1)*sizeof(int));
    if (tmp==NULL) exit(100);
    tmp[*size]=data;
    (*size)=*size+1;
    return tmp;
}