from decimal import Decimal, setcontext, getcontext
class MyNewSerializer(serializers.Serializer):
total_value_base = serializers.SerializerMethodField()
total_outgoing_value_base = serializers.DecimalField(
max_digits=38,
decimal_places=8,
source="value_sent",
)
total_incoming_value = serializers.DecimalField(
max_digits=38,
decimal_places=4,
source="value_received",
)
def get_total_value_base(self, obj):
total = Decimal(obj.value_received) + Decimal(
obj.value_sent
)
# Values of above objects
# obj.value_received = 425933085766969760747388.45622168
# obj.value_sent = 0
# total = 425933085766969760747388.4562
dec = Decimal(str(total))
return round(dec, 8)
但这会引发错误:
return round(dec, 8)
decimal.InvalidOperation: [<class 'decimal.InvalidOperation'>]
当我执行以下操作时,此问题已修复:
def get_total_value_base(self, obj):
# the below line fixes the issue
getcontext().prec = 100
total = Decimal(obj.value_received) + Decimal(
obj.value_sent
)
# Values of above objects
# obj.value_received = 425933085766969760747388.45622168
# obj.value_sent = 0
# total = 425933085766969760747388.4562
dec = Decimal(str(total))
return round(dec, 8)
我想提高该类以及其他类似类中所有值的精度。
我如何使用基类或覆盖整个文件或文件中的各个类的 Decimal 类来做到这一点?
我希望提高文件中各种不同类中存在的 100 个变量的小数精度。
可以通过以下方式完成:
from decimal import Decimal, getcontext
class HighDecimalPrecision:
def __getattribute__(self, name):
# Set the precision for Decimal operations
getcontext().prec = 50
return super().__getattribute__(name)
class MyNewSerializer(HighDecimalPrecision, serializers.Serializer):
...