如果字段匹配则更新和删除

Question

我明白，在没有任何工作要求的情况下提出问题有点粗鲁，但是我有点难过，我需要一些帮助。

如果另一个表中的另一个字段等于1，我需要从mysql表中删除一行

我有两张桌子table_1和table_2

table_1有两个领域location和events

和table_2有一个名为location的领域，与location上的table_1相同

如果字段table_2与location和table_1 = 1相同，我想从events中删除一行或多行

就像是：

if `events` = 1 in `table_1` in 'location' `*`;
    delete row(s) from `table_2`
    where `location` is the same as `location` in `table_1`

Answer 1

DELETE t2
  FROM `table2` t2
  JOIN `table1` t1 ON t1.events = 1
                  AND t1.location = t2.location

Answer 2

试试这个：

delete from `table_2` 
   where location in (select location from `table_1` where events=1)

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编辑

DELETE t2 FROM `table_2` t2 
   JOIN `table_1` t1 ON t1.location = t2.location where t1.events=1