我想识别同一商品上的
TapGesture
和 LongPressGesture
。它工作正常,但有以下例外:LongPressGesture
在我指定的持续时间(0.25秒)后单独响应,但是当我将它与TapGesture
结合使用时,它至少需要1秒——我找不到一种使其响应更快的方法。这是一个演示:
这是它的代码:
struct ContentView: View {
@State var message = ""
var body: some View {
Circle()
.fill(Color.yellow)
.frame(width: 150, height: 150)
.onTapGesture(count: 1) {
message = "TAP"
}
.onLongPressGesture(minimumDuration: 0.25) {
message = "LONG\nPRESS"
}
.overlay(Text(message)
.font(.title).bold()
.multilineTextAlignment(.center)
.allowsHitTesting(false))
}
}
请注意,除了长按的持续时间(远长于 0.25 秒)之外,它工作正常。
有什么想法吗?预先感谢!
为了拥有一些适合项目中每个人需求的多手势,Apple 没有提供比普通手势更好的功能,将它们混合在一起以达到所需的手势有时会很棘手,这是一个救赎,工作没有问题或错误!
这里有一个自定义的零问题手势,称为interactionReader,我们可以将其应用到任何视图。 同时拥有LongPressGesture和TapGesture。
import SwiftUI
struct ContentView: View {
var body: some View {
Circle()
.fill(Color.yellow)
.frame(width: 150, height: 150)
.interactionReader(longPressSensitivity: 250, tapAction: tapAction, longPressAction: longPressAction, scaleEffect: true)
.animation(Animation.easeInOut(duration: 0.2))
}
func tapAction() { print("tap action!") }
func longPressAction() { print("longPress action!") }
}
struct InteractionReaderViewModifier: ViewModifier {
var longPressSensitivity: Int
var tapAction: () -> Void
var longPressAction: () -> Void
var scaleEffect: Bool = true
@State private var isPressing: Bool = Bool()
@State private var currentDismissId: DispatchTime = DispatchTime.now()
@State private var lastInteractionKind: String = String()
func body(content: Content) -> some View {
let processedContent = content
.gesture(gesture)
.onChange(of: isPressing) { newValue in
currentDismissId = DispatchTime.now() + .milliseconds(longPressSensitivity)
let dismissId: DispatchTime = currentDismissId
if isPressing {
DispatchQueue.main.asyncAfter(deadline: dismissId) {
if isPressing { if (dismissId == currentDismissId) { lastInteractionKind = "longPress"; longPressAction() } }
}
}
else {
if (lastInteractionKind != "longPress") { lastInteractionKind = "tap"; tapAction() }
DispatchQueue.main.asyncAfter(deadline: .now() + .milliseconds(50)) {lastInteractionKind = "none"}
}
}
return Group {
if scaleEffect { processedContent.scaleEffect(lastInteractionKind == "longPress" ? 1.5: (lastInteractionKind == "tap" ? 0.8 : 1.0 )) }
else { processedContent }
}
}
var gesture: some Gesture {
DragGesture(minimumDistance: 0.0, coordinateSpace: .local)
.onChanged() { _ in if !isPressing { isPressing = true } }
.onEnded() { _ in isPressing = false }
}
}
extension View {
func interactionReader(longPressSensitivity: Int, tapAction: @escaping () -> Void, longPressAction: @escaping () -> Void, scaleEffect: Bool = true) -> some View {
return self.modifier(InteractionReaderViewModifier(longPressSensitivity: longPressSensitivity, tapAction: tapAction, longPressAction: longPressAction, scaleEffect: scaleEffect))
}
}
发现这个老问题,因为我只需要做类似的事情,我想我会分享。我最终得到了这段代码,只要它不附加到按钮(它吸收一些手势),它似乎就可以很好地工作。将以下代码添加到图像或圆形或其他类似内容中,它将立即检测到轻击,或在 0.25 秒后检测到长按。 (请注意,这只会检测其中之一,而不是两者。)
.onTapGesture(count: 1) {
print("Tap Gesture. \(Date().timeIntervalSince1970)")
}
.simultaneousGesture(
LongPressGesture(minimumDuration: 0.25)
.onEnded() { value in
print("LongPressGesture started. \(Date().timeIntervalSince1970)")
}
.sequenced(before:TapGesture(count: 1)
.onEnded {
print("LongPressGesture ended. \(Date().timeIntervalSince1970)")
}))
我认为您之前问题的根源是点击手势必须“下降”到长按手势,这需要一点时间。这两个同时启动,但只有一个成功。
LongPressGesture 还有另一个完成功能,可以在用户第一次触摸时执行操作,并在最短的持续时间内再次执行操作。像这样的东西可以工作吗?
struct LongTapTest: View {
@State var message = ""
var body: some View {
Circle()
.fill(Color.yellow)
.frame(width: 150, height: 150)
.onLongPressGesture(minimumDuration: 0.25, maximumDistance: 50, pressing: { (isPressing) in
if isPressing {
// called on touch down
} else {
// called on touch up
message = "TAP"
}
}, perform: {
message = "LONG\nPRESS"
})
.overlay(Text(message)
.font(.title).bold()
.multilineTextAlignment(.center)
.allowsHitTesting(false))
}
}
嗯,这并不漂亮,但效果很好。它记录每次点击/按下的开始,如果它在 0.25 秒之前结束,则将其视为
TapGesture
,否则将其视为 LongPressGesture
:
struct ContentView: View {
@State var pressInProgress = false
@State var gestureEnded = false
@State var workItem: DispatchWorkItem? = nil
@State var message = ""
var body: some View {
Circle()
.fill(Color.yellow)
.frame(width: 150, height: 150, alignment: .center)
.overlay(Text(message)
.font(.title).bold()
.multilineTextAlignment(.center)
.allowsHitTesting(false))
.gesture(
DragGesture(minimumDistance: 0, coordinateSpace: .global)
.onChanged { _ in
guard !pressInProgress else { return }
pressInProgress = true
workItem = DispatchWorkItem {
message = "LONG\nPRESSED"
gestureEnded = true
}
DispatchQueue.main.asyncAfter(deadline: .now() + 0.25, execute: workItem!)
}
.onEnded { _ in
pressInProgress = false
workItem?.cancel()
guard !gestureEnded else { // moot if we're past 0.25 seconds so ignore
gestureEnded = false
return
}
message = "TAPPED"
gestureEnded = false
}
)
}
}
如果有人能想到一个实际使用
LongPressGesture
和 TapGesture
的解决方案,我会更喜欢!
我对延误感到恼火。肯定有适合给定问题的答案。但是,我遇到了一个问题,因为我的视图也在 ScrollView(或 UITableView)内,因此使用
simultaneousGesture
不是一个选项,因为我失去了滚动视图的能力。
但是在 @nicksarno 答案的基础上,我创建了一个自定义修饰符,并利用
onPressingChanged
闭包和自定义延迟。这样我就可以在调用本机 perform:
闭包之前触发长按操作。此外,通过这种方法,您可以添加视觉反馈(在我的例子中 - 长按时缩放视图)。很想听听你的想法。
使用方法很简单,只需将onLongPress替换为自定义修饰符即可:
Circle()
.fill(Color.yellow)
.frame(width: 150, height: 150)
.onTapGesture(count: 1) {
message = "TAP"
}
.onScalingLongPress {
message = "LONG\nPRESS"
}
实施:
import SwiftUI
extension View {
func onScalingLongPress(perform action: @escaping () -> Void) -> some View {
modifier(ScalingLongPressModifier(action: action))
}
}
struct ScalingLongPressModifier: ViewModifier {
@State private var longPressTask: Task<Void, Never>?
@State private var shouldScale: Bool = false
var scaleWhenPressed: Double = 0.975
var action: VoidCompletion
func body(content: Content) -> some View {
content
.scaleEffect(shouldScale ? scaleWhenPressed : 1.0)
.onLongPressGesture(
minimumDuration: 0.2,
maximumDistance: 50,
perform: {
// do nothing
},
onPressingChanged: { isPressing in
handlePressingChange(isPressing: isPressing)
})
}
@MainActor
private func handlePressingChange(isPressing: Bool) {
if isPressing {
longPressTask = Task {
// Wait and scale the view
try? await Task.sleep(nanoseconds: 200_000_000)
guard !Task.isCancelled else {
return
}
withAnimation(.spring()) {
shouldScale = true
}
// Wait and trigger the action
try? await Task.sleep(nanoseconds: 200_000_000)
guard !Task.isCancelled else {
return
}
action()
}
} else {
longPressTask?.cancel()
longPressTask = nil
withAnimation(.spring()) {
shouldScale = false
}
}
}
}