我需要按时间顺序对我的 json 数组进行排序,按它的 create_at 时间戳。
[{
"id": 1,
"message": "hello",
"company_id": 7,
"investor_id": 35,
"match_id": 2,
"created_at": "2015-07-01 12:56:34",
"updated_at": "2015-07-01 12:56:34"
}, {
"id": 2,
"message": "helloWorld",
"company_id": 7,
"investor_id": 35,
"match_id": 2,
"created_at": "2015-07-01 12:56:53",
"updated_at": "2015-07-01 12:56:53"
}, {
"id": 3,
"message": "sup",
"company_id": 7,
"investor_id": 35,
"match_id": 2,
"created_at": "2015-07-01 13:12:53",
"updated_at": "2015-07-01 13:12:53"
}, {
"id": 4,
"message": "sup",
"company_id": 7,
"investor_id": 35,
"match_id": 2,
"created_at": "2015-07-01 13:13:04",
"updated_at": "2015-07-01 13:13:04"
}, {
"id": 5,
"message": "sup",
"company_id": 7,
"investor_id": 35,
"match_id": 2,
"created_at": "2015-07-01 15:06:39",
"updated_at": "2015-07-01 15:06:39"
}, {
"id": 1,
"message": "yo yo ",
"investor_id": 35,
"company_id": 7,
"match_id": 2,
"created_at": "2015-07-01 22:09:36",
"updated_at": "-0001-11-30 00:00:00"
}, {
"id": 2,
"message": "sup nigga",
"investor_id": 35,
"company_id": 7,
"match_id": 2,
"created_at": "2015-07-01 14:00:00",
"updated_at": "-0001-11-30 00:00:00"
}]
谁能教我如何在 stackoverflow 中尝试很多解决方案。他们中的许多人说数组不能与“sortBy”一起使用。
这是我的代码的一部分:
$companyMessage = Company_Message::where('match_id','=',$match_id);
$investorMessage = Investor_Message::where('match_id','=',$match_id);
$message = array();
if($companyMessage->count()>0 || $investorMessage->count() > 0){
if($lastActivityDate == null ){
//load all messages before
if($companyMessage !=null){
foreach ($companyMessage->get() as $cm) {
array_push($message,$cm);
}
}
if($investorMessage !=null){
foreach($investorMessage->get() as $im){
array_push($message,$im);
}
}
return $message ;
}
collection api
而不是 array
来完成此操作,并将项目添加到集合中并在集合上使用 sortBy
方法,
$col = new \Illuminate\Database\Eloquent\Collection();
if ($companyMessage != null) {
foreach($companyMessage - > get() as $cm) {
$col->add($cm);
}
}
if ($investorMessage != null) {
foreach($investorMessage - > get() as $im) {
$col->add($im);
}
}
$col = $col->sortBy('created_at');
//return the json
return Response::json($jsonArr->toArray());
--- 或 ----
试试这个,但我没有测试过。如果这有效,那么这将是最好的方法。
$companyMessage = Company_Message::where('match_id','=',$match_id);
$investorMessage = Investor_Message::where('match_id','=',$match_id);
//$companyMessage & $investorMessage both are laravel database collection,
// so you can use merge method on collection to merge these two collections.
$allResults = $companyMessage->merge($investorMessage);
//use laravel collection sort method to sort the collection by created_at
$allResults = $allResults->sortBy('created_at');
//return the json
return Response::json($allResults->toArray());
if($companyMessage !=null){
foreach ($companyMessage->get() as $cm) {
array_push($message,$cm);
}
}
if($investorMessage !=null){
foreach($investorMessage->get() as $im){
array_push($message,$im);
}
}
$message = array_values(array_sort($message, function ($value) {
return $value['created_at'];
}));
嘿伙计,我找到了一个更好的解决方案来对数组进行排序。答案可以在 laravel 文档中找到