用cURL的用户名和密码登录Gitlab。

问题描述 投票:8回答:3

为了在Docker中对Gitlab实例进行命令行工具测试,我想使用用户名和密码登录Gitlab,并抓取创建的会话来验证我的API请求。

因此,我做了如下操作。

  1. 在用户登录页面上使用 curl -i http://localhost:8080/users/sign_in -s
  2. 给我 _gitlab_session 从头
  3. 给我 authenticity_token 从登录表
  4. 发送第二个带有

curl 'http://localhost:8080/users/sign_in' \
  -H "_gitlab_session=${cookie}" \
  -H 'Origin: http://localhost:8080' \
  -H 'Content-Type: application/x-www-form-urlencoded' \
  -H 'Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8' \
  -H 'Referer: http://localhost:8080/users/sign_in' \
  -H 'Connection: keep-alive' \
  --data-urlencode "authenticity_token=${token}" \
  --data-urlencode "user[login]=root" \
  --data-urlencode "user[password]=12341234" \
  --data-urlencode "user[remember_me]=0"

但我得到的不是一个有效的用户登录,而是一个

422 - The change you requested was rejected.

而在日志文件中,我看到

==> gitlab-rails/production.log <==
Started POST "/users/sign_in" for 172.17.0.1 at 2017-12-23 00:22:16 +0000
Processing by SessionsController#create as HTML
Parameters: {"authenticity_token"=>"[FILTERED]", "user"=>{"login"=>"root", "password"=>"[FILTERED]", "remember_me"=>"0"}}
Can't verify CSRF token authenticity
Completed 422 Unprocessable Entity in 125ms (ActiveRecord: 7.8ms)

==> gitlab-rails/production_json.log <==
{"method":"POST","path":"/users/sign_in","format":"html","controller":"SessionsController",  
"action":"create","status":422,"error":" 
ActionController::InvalidAuthenticityToken:ActionController::InvalidAuthenticityToken",
"duration":126.29,"view":0.0,"db":7.78,"time":"2017-12-23T00:22:16.039Z",
"params":{"authenticity_token":"[FILTERED]","user":{"login":"root","password":"
[FILTERED]","remember_me":"0"}},"remote_ip":"172.17.0.1",
"user_id":1,"username":"root"}

==> gitlab-rails/production.log <==

ActionController::InvalidAuthenticityToken (ActionController::InvalidAuthenticityToken):
  lib/gitlab/middleware/multipart.rb:93:in `call'
  lib/gitlab/request_profiler/middleware.rb:14:in `call'
  lib/gitlab/middleware/go.rb:18:in `call'
  lib/gitlab/etag_caching/middleware.rb:11:in `call'
  lib/gitlab/middleware/read_only.rb:31:in `call'
  lib/gitlab/request_context.rb:18:in `call'
  lib/gitlab/metrics/requests_rack_middleware.rb:27:in `call'

我假设我在第二个请求中忘了传递一个必要的成分--但我想不通,是哪一个。

curl gitlab csrf
3个回答
15
投票

通过其他答案和评论的一些有用的提示,我终于想到了这个解决方案。

gitlab_host="http://localhost:8080"
gitlab_user="root"
gitlab_password="12341234"

# curl for the login page to get a session cookie and the sources with the auth tokens
body_header=$(curl -c cookies.txt -i "${gitlab_host}/users/sign_in" -s)

# grep the auth token for the user login for
#   not sure whether another token on the page will work, too - there are 3 of them
csrf_token=$(echo $body_header | perl -ne 'print "$1\n" if /new_user.*?authenticity_token"[[:blank:]]value="(.+?)"/' | sed -n 1p)

# send login credentials with curl, using cookies and token from previous request
curl -b cookies.txt -c cookies.txt -i "${gitlab_host}/users/sign_in" \
    --data "user[login]=${gitlab_user}&user[password]=${gitlab_password}" \
    --data-urlencode "authenticity_token=${csrf_token}"

# send curl GET request to personal access token page to get auth token
body_header=$(curl -H 'user-agent: curl' -b cookies.txt -i "${gitlab_host}/profile/personal_access_tokens" -s)
csrf_token=$(echo $body_header | perl -ne 'print "$1\n" if /authenticity_token"[[:blank:]]value="(.+?)"/' | sed -n 1p)

# curl POST request to send the "generate personal access token form"
# the response will be a redirect, so we have to follow using `-L`
body_header=$(curl -L -b cookies.txt "${gitlab_host}/profile/personal_access_tokens" \
    --data-urlencode "authenticity_token=${csrf_token}" \
    --data 'personal_access_token[name]=golab-generated&personal_access_token[expires_at]=&personal_access_token[scopes][]=api')

# Scrape the personal access token from the response HTML
personal_access_token=$(echo $body_header | perl -ne 'print "$1\n" if /created-personal-access-token"[[:blank:]]value="(.+?)"/' | sed -n 1p)

根据... GitLab API文档 你现在可以使用会话cookie来验证API请求。

curl --header "Private-Token: ${personal_access_token}" https://gitlab.example.com/api/v4/projects

一些提示:

  • 我先是搞混了 curl -c file (它从头文件中读取cookie并将其写入文件)与 curl -b file (它使用文件中的cookie并与请求一起发送)
  • 遗憾的是,我没有找到一个能与 sed 所以我必须使用 perl 这里。
  • 在Chrome浏览器中使用开发者控制台并复制一个 POST 请求作为curl命令非常有用。https:/www.alexkras.comcopy-any-api-call-as-curl-request-with-chrome-developer-tools

1
投票

在我的测试中,有 4 个来自登录页面的 cookie,其中 3 个看起来像是令牌,如果除了 _gitlab_session cookie 之外,至少还有 1 个 cookie 是成功登录所需要的,我也不会感到惊讶。但与其费心去找正确的所需cookie组合,我认为最好是让curl自动处理cookie,比如--cookie-jar和--cookie(那么所有的cookie都应该是正确的)--此外,登录页面上有3个不同的authenticity_token,你确定你获取的是正确的吗?

这里有一个经过测试的 PHP 示例,使用的是 hhb_curl (只需替换第10行的用户名和密码& 11)。

<?php
declare(strict_types = 1);
require_once ('hhb_.inc.php');
$hc = new hhb_curl ( '', true );
$html = $hc->exec ( 'https://gitlab.com/users/sign_in' )->getStdOut ();
$domd = @DOMDocument::loadHTML ( $html );
$inputs = getDOMDocumentFormInputs ( $domd, true, false ) ['new_user'];
// var_dump ( $inputs );
$inputs ['user[login]'] = '???';
$inputs ['user[password]'] = '???';
$html = $hc->setopt_array ( array (
        CURLOPT_POST => 1,
        CURLOPT_POSTFIELDS => http_build_query ( $inputs ) 
) )->exec ()->getStdOut ();
echo $html;
$domd = @DOMDocument::loadHTML ( $html );
$xp = new DOMXPath ( $domd );
foreach ( $xp->query ( '//div[contains(@class,"flash-alert")]' ) as $loginError ) {
    var_dump ( "login error: ", trim($loginError->textContent) );
}

function getDOMDocumentFormInputs(\DOMDocument $domd, bool $getOnlyFirstMatches = false, bool $getElements = true): array {
    // :DOMNodeList?
    if (! $getOnlyFirstMatches && ! $getElements) {
        throw new \InvalidArgumentException ( '!$getElements is currently only implemented for $getOnlyFirstMatches (cus im lazy and nobody has written the code yet)' );
    }
    $forms = $domd->getElementsByTagName ( 'form' );
    $parsedForms = array ();
    $isDescendantOf = function (\DOMNode $decendant, \DOMNode $ele): bool {
        $parent = $decendant;
        while ( NULL !== ($parent = $parent->parentNode) ) {
            if ($parent === $ele) {
                return true;
            }
        }
        return false;
    };
    // i can't use array_merge on DOMNodeLists :(
    $merged = function () use (&$domd): array {
        $ret = array ();
        foreach ( $domd->getElementsByTagName ( "input" ) as $input ) {
            $ret [] = $input;
        }
        foreach ( $domd->getElementsByTagName ( "textarea" ) as $textarea ) {
            $ret [] = $textarea;
        }
        foreach ( $domd->getElementsByTagName ( "button" ) as $button ) {
            $ret [] = $button;
        }
        return $ret;
    };
    $merged = $merged ();
    foreach ( $forms as $form ) {
        $inputs = function () use (&$domd, &$form, &$isDescendantOf, &$merged): array {
            $ret = array ();
            foreach ( $merged as $input ) {
                // hhb_var_dump ( $input->getAttribute ( "name" ), $input->getAttribute ( "id" ) );
                if ($input->hasAttribute ( "disabled" )) {
                    // ignore disabled elements?
                    continue;
                }
                $name = $input->getAttribute ( "name" );
                if ($name === '') {
                    // echo "inputs with no name are ignored when submitted by mainstream browsers (presumably because of specs)... follow suite?", PHP_EOL;
                    continue;
                }
                if (! $isDescendantOf ( $input, $form ) && $form->getAttribute ( "id" ) !== '' && $input->getAttribute ( "form" ) !== $form->getAttribute ( "id" )) {
                    // echo "this input does not belong to this form.", PHP_EOL;
                    continue;
                }
                if (! array_key_exists ( $name, $ret )) {
                    $ret [$name] = array (
                            $input 
                    );
                } else {
                    $ret [$name] [] = $input;
                }
            }
            return $ret;
        };
        $inputs = $inputs (); // sorry about that, Eclipse gets unstable on IIFE syntax.
        $hasName = true;
        $name = $form->getAttribute ( "id" );
        if ($name === '') {
            $name = $form->getAttribute ( "name" );
            if ($name === '') {
                $hasName = false;
            }
        }
        if (! $hasName) {
            $parsedForms [] = array (
                    $inputs 
            );
        } else {
            if (! array_key_exists ( $name, $parsedForms )) {
                $parsedForms [$name] = array (
                        $inputs 
                );
            } else {
                $parsedForms [$name] [] = $tmp;
            }
        }
    }
    unset ( $form, $tmp, $hasName, $name, $i, $input );
    if ($getOnlyFirstMatches) {
        foreach ( $parsedForms as $key => $val ) {
            $parsedForms [$key] = $val [0];
        }
        unset ( $key, $val );
        foreach ( $parsedForms as $key1 => $val1 ) {
            foreach ( $val1 as $key2 => $val2 ) {
                $parsedForms [$key1] [$key2] = $val2 [0];
            }
        }
    }
    if ($getElements) {
        return $parsedForms;
    }
    $ret = array ();
    foreach ( $parsedForms as $formName => $arr ) {
        $ret [$formName] = array ();
        foreach ( $arr as $ele ) {
            $ret [$formName] [$ele->getAttribute ( "name" )] = $ele->getAttribute ( "value" );
        }
    }
    return $ret;
}
  • 它目前的输出是

    string(13) "login error: " string(26) "Invalid Login or password."

意味着????不是一个有效的用户名& 密码组合。


0
投票

在gitlab中创建access_token或private_token,你可以在URL中使用它。

bash <(curl -s full-path-to-raw-url?private_token=your_private_token) param1 param2

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