使用.nextLine（）在数组跳过行中存储值

Question

我之前的问题已经结束，但是建议的答案对我没有太大帮助。不便之处，敬请原谅。

我正在尝试将fname，lname，address，city，state和zip存储在数组customerData[30][6]中。但是，似乎在我输入信息的地方跳过了行。

代码

public void addCustomer() throws IOException {
        Scanner scan = new Scanner(System.in);
        int numCustomers = 0;
        String[][] customerData = new String[30][7];

        System.out.println("how many customers");
        numCustomers = scan.nextInt();

        BufferedWriter writer = new BufferedWriter(
                new FileWriter("/Users/simonshamoon/eclipse-workspace/Final Project/src/customerdata.txt"));

        BufferedWriter loginWriter = new BufferedWriter(
                new FileWriter("/Users/simonshamoon/eclipse-workspace/Final Project/src/userlogin.txt"));

        for (int i = 0; i < numCustomers; i++) {

            System.out.println("enter customer data (fname, lname, address, city, state, zip)");

            for (int j = 0; j < customerData[i].length; j++) {
                customerData[i][j] = scan.nextLine();

            }
            writer.write(customerData[i][0] + ", " + customerData[i][1] + ", " + customerData[i][2] + ", "
                    + customerData[i][3] + ", " + customerData[i][4] + ", " + customerData[i][5] + "\n");

            loginWriter.write(customerData[i][0].charAt(0) + customerData[i][1] + ", " + rand.nextInt(10001) + "ASU"
                    + ", Customer" + "\n");

        }

        writer.flush();
        writer.close();
        loginWriter.flush();
        loginWriter.close();

    }

输出

how many customers
1
enter customer data (fname, lname, address, city, state, zip)
fname
lname
123 address dr
city
state
zip
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 0
    at java.base/java.lang.StringLatin1.charAt(StringLatin1.java:48)
    at java.base/java.lang.String.charAt(String.java:709)
    at Employee.addCustomer(Employee.java:156)
    at Employee.displayEmployeeMenu(Employee.java:196)
    at BasicMethods.promptUser(BasicMethods.java:48)
    at Shop.main(Shop.java:8)

我想要它以便customerData[i][0] = fname，customerData[i][1] = lname等。我尝试使用.nextLine和数组大小，但是我认为问题出在address中所需的空间。

Answer 1

因此您在这里创建客户数据：

for (int j = 0; j < customerData[i].length; j++) {
    customerData[i][j] = scan.nextLine();
}

这是使用charAt的编写者代码：

loginWriter.write(customerData[i][0].charAt(0) + customerData[i][1] + ", " + rand.nextInt(10001) + "ASU" + ", Customer" + "\n");

所以看起来customerData[i][0]是一个空字符串，因为它是charAt的唯一使用，它会引发索引异常。

我建议您要么输出单个数据项，要么更好，使用调试器逐步执行代码。

由于您没有显示周围的代码（scan是如何创建的；也许它被重用，但同时又意外关闭了？），我们只能做出合理的猜测。