SQL 分组在一起，因此数据不会重复

Question

将数据存储在表中，并尝试将其查询出来，以便读取数据，例如 Motrin |毫克 | 25 | 25 4 |日 |疼痛，排成一排。从图像中...我将它们全部放在“答案”栏下。我的查询将它们全部显示出来......但它重复了数据。任何人都可以帮忙将其分组到 DrilldownQuestionID 下吗？

以下是我创建的示例数据：

练习ID	患者ID	父页面ID	父页码	问题ID	深入分析问题ID	深入分析AnsRecordID	遇到ID	回答
1	111111	48	5	1475	2091	1	遭遇1	泰诺
1	111111	48	5	1475	2092	1	遭遇1	毫克
1	111111	48	5	1475	2093	1	遭遇1	500
1	111111	48	5	1475	2094	1	遭遇1	3
1	111111	48	5	1475	2095	1	遭遇1	日
1	111111	48	5	1475	2096	1	遭遇1	头痛
1	111111	48	5	1475	2091	2	遭遇1	美林
1	111111	48	5	1475	2092	2	遭遇1	毫克
1	111111	48	5	1475	2093	2	遭遇1	25
1	111111	48	5	1475	2094	2	遭遇1	4
1	111111	48	5	1475	2095	2	遭遇1	日
1	111111	48	5	1475	2096	2	遭遇1	疼痛

下面是我的查询；

    select distinct j.Answer as Name, 
    n.Answer as Dosage,
    k.Answer as [Dosage Unit], 
    o.Answer as [How Many],
    l.Answer as [How Often], 
    m.Answer as [Taken For]
from
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID  
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2091
    where a.EncounterID = @EncounterID) as j
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID  
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2093
    where a.EncounterID = @EncounterID) as n
        on j.EncounterID = n.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID 
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2092
    where a.EncounterID = @EncounterID) as k
        on n.encounterID = k.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID  
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2094
    where a.EncounterID = @EncounterID) as o
        on k.EncounterID = o.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID 
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2095
    where a.EncounterID = @EncounterID) as l
        on o.encounterID = l.EncounterID
        join
    (select isnull(a.[Answer],'') as Answer, 
        a.EncounterID 
    from C_ItemDrillDown c join D_AWVAnswers a 
        on c.ItemDrilldownID = a.DrilldownQuestionID 
        and a.QuestionID = 1475 
        and a.DrilldownQuestionID = 2096
    where a.EncounterID = @EncounterID) as m
        on l.encounterID = m.EncounterID

我想要的结果是：

姓名	用量	剂量单位	有多少	多久一次	所为
泰诺	500	毫克	3	日	头痛
美林	25	毫克	4	日	疼痛

Answer 1

所以看起来你正在追求直接的枢轴，如下所示：

select 
  max(case when DrilldownQuestionID = 2091 then Answer end) [Name],
  max(case when DrilldownQuestionID = 2092 then Answer end) [Dosage Unit],
  max(case when DrilldownQuestionID = 2093 then Answer end) Dosage,
  max(case when DrilldownQuestionID = 2094 then Answer end) [How Many],
  max(case when DrilldownQuestionID = 2095 then Answer end) [How Often],
  max(case when DrilldownQuestionID = 2096 then Answer end) [Taken For]
from t
group by DrilldownAnsRecordID;

我省略了多余的（问题）列，如果您需要使用它们，您也可以对它们进行分组。

结果：

参见演示小提琴