用java解密wav文件对Python脚本加密的文件不起作用

Question

我正在尝试解密用Python脚本加密的WAV文件。我在 Java 和 Python 中使用相同的硬编码密钥。我在两个不同的地方使用两个不同的 Python 脚本，Java 中的解密适用于使用一个 Python 脚本加密的 WAV 文件，但它不适用于另一个 Python 脚本 WAV 文件。我正在分享这两个 Python 脚本。 这是 Java 解密所用的 Python 脚本 Python 脚本 A

predefined_key = bytes.fromhex('ABC')

def encrypt_file(mixedRecordingPathName, key):
    iv = b'1234567890123456'
    backend = default_backend()
    cipher = Cipher(algorithms.AES(key), modes.CFB(iv), backend=backend)
    encryptor = cipher.encryptor()

    with open(mixedRecordingPathName, 'rb') as f:
        data = f.read()

    padder = padding.PKCS7(algorithms.AES.block_size).padder()
    padded_data = padder.update(data) + padder.finalize()

    encrypted_data = encryptor.update(padded_data) + encryptor.finalize()

    encrypted_file_path = mixedRecordingPathName

    with open(encrypted_file_path, 'wb') as f:
        f.write(iv + encrypted_data)

    return encrypted_file_path

这是脚本B（Java解密不起作用）

from cryptography.hazmat.backends import default_backend
from cryptography.hazmat.primitives.ciphers import Cipher, algorithms, modes
from cryptography.hazmat.primitives import padding
import sys

def encrypt_file(mixedRecordingPathName, key):
    iv = b'1234567890123456'  
    backend = default_backend()
    cipher = Cipher(algorithms.AES(key), modes.CFB(iv), backend=backend)
    encryptor = cipher.encryptor()

    with open(mixedRecordingPathName, 'rb') as f:
        data = f.read()


    padder = padding.PKCS7(algorithms.AES.block_size).padder()
    padded_data = padder.update(data) + padder.finalize()


    encrypted_data = encryptor.update(padded_data) + encryptor.finalize()

    decrypted_file_path = mixedRecordingPathName

    with open(decrypted_file_path, 'wb') as f:
        f.write(iv + encrypted_data)

    return decrypted_file_path

if __name__ == "__main__":
    key = bytes.fromhex('ABC')
    mixedRecordingPathName = sys.argv[1]     
    encrypt_file(mixedRecordingPathName, key)

这是 Java 代码，我使用相同的密钥解密波形文件

   private boolean decrypt(int cipherMode, String hexKey, File inputFile, File outputFile) {
        boolean fileProcessedSuccessfully = false;
        FileOutputStream outputStream = null;
        FileInputStream inputStream = null;

        try {
            byte[] keyBytes = hexStringToByteArray(hexKey);
            Key secretKey = new SecretKeySpec(keyBytes, "AES");
            Cipher cipher = Cipher.getInstance("AES/CFB/NoPadding");

            inputStream = new FileInputStream(inputFile);

            byte[] iv = new byte[16];
            inputStream.read(iv); // read IV from the start of the file
            IvParameterSpec ivSpec = new IvParameterSpec(iv);
            cipher.init(cipherMode, secretKey, ivSpec);

            byte[] inputBytes = new byte[(int)inputFile.length() - 16];
            inputStream.read(inputBytes);

            byte[] outputBytes = cipher.doFinal(inputBytes);
            outputStream = new FileOutputStream(outputFile);
            outputStream.write(outputBytes);
            fileProcessedSuccessfully = true;
        } catch (Exception e) {
            logger.error("Exception Occurred While Decrypting File: " + inputFile.getName(), e);
        } finally {
            try {
                if (inputStream != null) {
                    inputStream.close();
                }
            } catch (Exception e) {
                logger.error("Exception Occurred while Closing Input Stream after Recording Decryption: " + inputFile.getName(), e);
            }

            try {
                if (outputStream != null) {
                    outputStream.close();
                }
            } catch (Exception e) {
                logger.error("Exception Occurred while Closing Output Stream after Recording Decryption: " + inputFile.getName(), e);
            }
        }

        return fileProcessedSuccessfully;
    }

    private byte[] hexStringToByteArray(String s) {
        int len = s.length();
        byte[] data = new byte[len / 2];
        for (int i = 0; i < len; i += 2) {
            data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4)
                    + Character.digit(s.charAt(i + 1), 16));
        }
        return data;
    }
}

这是我在邮递员中收到的小回复样本

所以我的问题是为什么Java解密方法适用于脚本A但不适用于脚本B？我在这里做错了什么

Answer 1

感谢您的帮助。我能够找到原因或问题。我试图在 Postman 中播放音频 wav 文件，但 API 返回随机数据，如上图所示，由于某种原因，Postman 无法处理要播放的文件。我以为解密没有正确完成。

在我的 Web 应用程序（语音录制解决方案）中部署并运行代码后，解密和音频文件就可以播放。

再次感谢大家的帮助。

PS：两个脚本都可以工作。