为什么列表理解在第二次按下后给我一个类型错误

Question

我正在尝试在 pygame 中制作一个计算器。我用列表理解制作了数学内容：

[a - b for a, b in zip(numbers, numbers[1:])]

,

但是在 Pygame 窗口上，每按三次任何数学符号就会给出：

TypeError: unsupported operand type(s) for -: 'list' and 'int'

我的代码：

import pygame
pygame.font.init()

width,height=1200,650
win=pygame.display.set_mode((width,height))

bg=pygame.Rect(0,0,width,height)

Npad_w, Npad_h=75,75


number1=0

font=pygame.font.SysFont("comic sans",50)
def draw(Npad1,Npad_sub,number_text):

    pygame.draw.rect(win, "dark red", bg)
    pygame.draw.rect(win,"pink",Npad1)

    pygame.draw.rect(win,"pink",Npad_sub)

    text=font.render(number_text,1,"white")
    win.blit(text,(width/2-200,height/2-Npad_h*3))


    pygame.display.update()

def main():
    run = True

    Npad1=pygame.Rect(width/2-300,height/2-Npad_h,Npad_w,Npad_h)
    
    Npad_sub=pygame.Rect(width/2-300,height/2-Npad_h+100,Npad_w*2,Npad_h)

    

    number_text=""
    number=[]
    second=False
    
    
    numbers=[]
    times=0
    action=0
    times_pressed=1
    
    
    clock=pygame.time.Clock()

    while run:
        clock.tick(60)

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                run=False
                break

            if event.type == pygame.MOUSEBUTTONDOWN:
               mouseX,mouseY=pygame.mouse.get_pos()  


               if Npad1.collidepoint(pygame.mouse.get_pos())  :
                number.append("1")
                print(number)
                number_text="".join(number)
                mouseX=0
                mouseY=0

               elif Npad_sub.collidepoint(pygame.mouse.get_pos()):
                 if second == False and number != "":
                  times_pressed+=1
                  numbers.append(int(number_text))
                  number_text=""
                  number.clear()
                  times += 1
                  if times_pressed<=2:
                    action = 1


            if times ==2 and action==1:
              number1=([a - b for a, b in zip(numbers, numbers[1:])])
              print(number1)
              numbers.clear()
              numbers.append(number1)
              times = 1
              times_pressed+=1



        draw(Npad1,Npad_sub,number_text)

        
    pygame.quit()

if __name__ == "__main__":
    main()       

如果大家有什么想法，请反馈。

（这是我可以编写的最小代码，并且可以重现，抱歉）

Answer 1

问题在这里：

numbers.append(number1)

- 您将

number1

（这是一个

list

）附加到

numbers

，它只需要整数。如果你想连接列表，你应该使用

extend

，如下所示：

numbers.extend(number1)