通过子查询中的属性过滤边缘-Orientdb sql

Question

我具有以下OrientDB SQL查询，该查询返回用户#12:0的所有朋友的用户名和国家/地区。

select 
   username, country 
from (select 
         expand( both('friends') ) 
      from 
         users 
      where 
         @rid = #12:0)

但是friends边具有带整数的属性years。我只想要#12:0的那些有friends.years > 3的朋友。

我已经尝试过

SELECT username, country from (SELECT expand(outE('friends')[years > 3].inV()) FROM #12:0)

SELECT username, country from (SELECT expand(both('friends')[years = 2]) FROM #12:0)

以及同一查询中的各种内容。

谢谢大家！

Answer 1

create class User extends V
create property User.username string
create property User.country string

create class friends extends E
create property friends.year integer  


create vertex User content {'username':'u1', 'country':'PT'}
create vertex User content {'username':'f1', 'country':'AW'}
create vertex User content {'username':'f2', 'country':'CN'}

create edge friends 
from (select from User where username = 'u1')
to (select from User where username = 'f1')
content {'years':3}

create edge friends 
from (select from User where username = 'f2')
to (select from User where username = 'u1')
content {'years':4}

我相信这是您的情况。您可以：

select expand(bothE('friends')[years = 3].inV()) 
from (select from User where username = 'u1')

但是，据我所知，尚不支持以下功能：

select expand(bothE('friends')[years > 3].inV()) 
from (select from User where username = 'u1')

Answer 2

另一个选择是用另一个嵌套查询来包装核心查询：

select * from (
select expand(both('friends')) 
from (select from User where username = 'u1')
)
where years > 3