获取复选框tktinter的值

Question

我试图在我的tktinter python项目中获取一个复选框的值，但是每次我尝试打印该值时，它都会空白。请帮助，谢谢。

（（我制作了另一个标签，上面印有'值应该在上面'，以确保每次调用函数时标签本身都在印刷。

这里是代码

from tkinter import *
from tkinter.ttk import *
import tkinter as tk  # python 3

class SeaofBTCapp(tk.Tk):

    def __init__(self, *args, **kwargs):
        tk.Tk.__init__(self, *args, **kwargs)
        container = tk.Frame(self)
        container.pack(side="top", fill="both", expand=True)
        container.grid_rowconfigure(0, weight=1)
        container.grid_columnconfigure(0, weight=1)
        self.frames = {}
        for F in (StartPage,):
            frame = F(container, self)

            self.frames[F] = frame

            frame.grid(row=0, column=0, sticky="nsew")

        self.show_frame(StartPage)

    def show_frame(self, cont):
        frame = self.frames[cont]
        frame.tkraise()
        frame.winfo_toplevel().geometry("1024x720")
        frame.configure(bg='#333130')


class StartPage(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        c = Canvas(self, height=50, width=102400, bg="#333130")
        c.pack()
        newtaskbutton = tk.Button(self, text='New Task', command=lambda: taskcreator())
        newtaskbutton_window = c.create_window(600, 12.5, anchor=tk.NE, window=newtaskbutton)

def taskcreator():
    global screen
    screen = Tk()
    screen.geometry('720x640')
    var = StringVar()
    option1 = tk.Checkbutton(screen, text="Size 11", variable=var, onvalue="Yes", offvalue="No")
    option1.deselect()
    option1.pack()
    you = Button(screen, text='check value', command=lambda: assign(var))
    you.place(x=100, y=100)

def assign(var):
    theoption = var.get()
    mylabel = tk.Label(screen, text=theoption)
    mylabel.pack()
    alabel = tk.Label(screen, text="The value should be above")
    alabel.pack()


app = SeaofBTCapp()
app.mainloop()

Answer 1

问题是您正在创建Tk的两个实例。第一个是您创建SeaofBTCapp的实例时，第二个是您执行screen = Tk()的位置。