无法通过用户输入打破 while 循环（Python）

Question

我正在学习在 while 循环中使用函数。我的目标是要求用户在 while 循环内输入，并将输入用作函数中的参数。但是如果任何时刻的输入是 == 'q'，则循环应该终止。 功能如下：

def make_album(artist_name, album_name, tracks = None):
    if tracks:
        album = {
            'artist': artist_name,
            'album': album_name,
            'number of tracks': tracks
        }
        return album
    else:
        album = {
            'artist': artist_name,
            'album': album_name,
            
        }
        return album

它被放置在 while 循环内：

create_album = True
while create_album:
    
    artist = input("Enter atrist's name: ").title()
    if artist == 'q'.lower():
        create_album = False
        
    album = input("Enter album's name: ").capitalize()
    if album == 'q'.lower():
        create_album = False
        
    number_of_tracks = input("(Optional) Enter number of tracks: ")
    if number_of_tracks =='q'.lower():
        create_album = False
    elif number_of_tracks:
        print(make_album(artist, album, number_of_tracks))
    else:
        print(make_album(artist, album))

尽管每个输入都会使用 if 语句进行检查，并且如果输入是“q”，则应将 create_album 的值更改为 False，但它仅在代码的最后部分正常工作：

number_of_tracks = input("(Optional) Enter number of tracks: ")
    if number_of_tracks =='q'.lower():
        create_album = False

如何修复程序，以便在用户输入“q”时随时终止 while 循环？

我尝试过改变各种方法来解决这个问题。

1)

    if artist == 'q'.lower():
        break

结果是：

Enter album's name: 

2)

    if artist == 'q'.title():
        create_album = False

    if artist == 'q':
        create_album = False

    if artist == 'Q':
        create_album = False

结果是：

Enter album's name: 

Answer 1

一旦您确定用户输入了“q”，您就将

create_album

设置为

False

，但随后您就会进入下一个输入。

您可以在

break

主体中添加

continue

，或者在本例中甚至添加

if

：

    if artist == 'q'.lower():
        create_album = False
        break

但是对于这段代码来说，拥有

create_album

确实没有任何意义。 相反，您可以将整个内容替换为：

while True:   
    artist = input("Enter atrist's name: ").title()
    if artist == 'q'.lower():
        break
        
    album = input("Enter album's name: ").capitalize()
    if album == 'q'.lower():
        break
        
    number_of_tracks = input("(Optional) Enter number of tracks: ")
    if number_of_tracks =='q'.lower():
        break
    elif number_of_tracks:
        print(make_album(artist, album, number_of_tracks))
    else:
        print(make_album(artist, album))