SELECT * FROM (
SELECT soi.value, srv.osp_id, soi.stya_id, eoax.estpt_id, eoax.discount, int_sero.id AS sero_id, 2 as attr_number
FROM srv_obj_attr_intermediate soi
JOIN estpt_objt_attr_xref eoax ON eoax.interest_rate = 1
JOIN attribute_types attl ON attl.id = eoax.attr_id
JOIN object_attribute_type_links oatl ON oatl.attr_id = attl.id
JOIN service_type_attributes sta ON sta.objt_attr_id = oatl.id
JOIN service_objects int_sero ON int_sero.id = soi.sero_id
JOIN services srv ON srv.id = int_sero.srv_id
JOIN order_event_types oet ON oet.code = 'CALC_INTERMEDIATE_ESTP'
WHERE eoax.ordet_id = oet.id AND eoax.objt_attr_id = sta.objt_attr_id
AND soi.stya_id = sta.id AND soi.value = 1
UNION
SELECT soa.value, srv.osp_id, soa.stya_id, eoax.estpt_id, eoax.discount, int_sero.id AS sero_id, 1 as attr_number
FROM srv_obj_attributes soa
JOIN estpt_objt_attr_xref eoax ON eoax.interest_rate = 1
JOIN attribute_types attl ON attl.id = eoax.attr_id
JOIN object_attribute_type_links oatl ON oatl.attr_id = attl.id
JOIN service_type_attributes sta ON sta.objt_attr_id = oatl.id
--LEFT JOIN srv_obj_attr_intermediate soi ON soi.stya_id = sta.id
--AND soi.value = 1
JOIN service_objects int_sero ON int_sero.id = soa.sero_id
JOIN services srv ON srv.id = int_sero.srv_id
JOIN order_event_types oet ON oet.code = 'CALC_INITIAL_ESTP'
WHERE eoax.ordet_id = oet.id AND eoax.objt_attr_id = sta.objt_attr_id
AND soa.stya_id = sta.id AND soa.value = 1 --AND soi.value IS NULL
)
) intrate ON intrate.estpt_id = estpt.id
AND intrate.sero_id = esero.sero_id
AND intrate.osp_id = srv.osp_id --This parameters are served. For this example we replaced srv.osp_id to 619771
此选择向我返回此记录
|VALUE |OSP_ID |STYA_ID |ESTPT_ID |DISCOUNT |SERO_ID |ATTR_NUMBER |
|---------------------------------------|-------------|-------------|---------------------------------------|---------------------------------------|-------------|---------------------------------------|
|1 |619771 |34659 |1812 |30 |3933326 |1 |
|1 |619771 |34659 |1812 |30 |3933327 |1 |
|1 |619771 |34659 |1916 |30 |3933326 |1 |
|1 |619771 |34659 |1916 |30 |3933327 |1 |
|1 |619771 |34659 |1987 |30 |3933326 |1 |
|1 |619771 |34659 |1987 |30 |3933327 |1 |
|1 |619771 |34659 |2027 |30 |3933326 |1 |
|1 |619771 |34659 |2027 |30 |3933327 |1 |
|1 |619771 |34659 |2028 |30 |3933326 |1 |
|1 |619771 |34659 |2028 |30 |3933327 |1 |
|1 |619771 |34659 |2029 |30 |3933326 |1 |
|1 |619771 |34659 |2029 |30 |3933327 |1 |
|1 |619771 |34659 |1812 |40 |3933327 |2 |
|1 |619771 |34659 |1916 |40 |3933327 |2 |
|1 |619771 |34659 |1987 |40 |3933327 |2 |
|1 |619771 |34659 |2027 |40 |3933327 |2 |
|1 |619771 |34659 |2028 |40 |3933327 |2 |
|1 |619771 |34659 |2029 |40 |3933327 |2 |
我需要在每个选择上添加校验，并具有自己的attr_number。基于此列，我需要返回记录。
如果用exists记录attr_number = 1，那么我应该只获取那些记录。
如果用do not exists记录attr_number = 1，那么我应该仅在attr_number = 2处获得记录。
我正试着解决我的问题，您可以看到推荐的行（left join和soi.value IS NULL在哪里），但是它不能像我描述的那样工作。他不检查记录是否存在。
是，我们应该使用union删除重复的行。
此选择在left outer join中使用。
rank()过滤结果集：select *
from (
select
t.*,
rank() over(
partition by osp_id, stya_id, espt_id, sero_id
order by attr_number desc
) rn
from (
-- your big `unioon` query
) t
) t
where rn = 1
由于您没有确切说出哪些列定义了组，所以我对partition进行了假设。
[您标记了Oracle 10g的问题。但是请注意，如果要使用Oracle 12c，则使用行限制子句会更简单：
select t.* from ( -- your big `unioon` query ) t order by rank() over( partition by osp_id, stya_id, espt_id, sero_id order by attr_number desc ) fetch first 1 rows with ties
analytical function：select *
from (
select
t.*,
Min(attr_number) over(
partition by value, stya_id, espt_id) as min_a
from (
-- your `union` query
) t
) t
where attr_number = min_a
干杯！