组2D数组数据通过列

问题描述 投票：0回答：2

array(8) { [6]=> array(7) { ["id"]=> string(2) "52" ["useridfrom"]=> string(3) "330" ["useridto"]=> string(3) "139" ["message"]=> string(10) "test" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336561645" ["messagetype"]=> string(6) "direct" } [7]=> array(7) { ["id"]=> string(2) "53" ["useridfrom"]=> string(3) "330" ["useridto"]=> string(3) "139" ["message"]=> string(8) "bye" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336561648" ["messagetype"]=> string(6) "direct" } [1]=> array(7) { ["id"]=> string(2) "30" ["useridfrom"]=> string(3) "329" ["useridto"]=> string(3) "139" ["message"]=> string(243) "Hi Bob" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1330942044" ["messagetype"]=> string(6) "direct" } [3]=> array(7) { ["id"]=> string(2) "42" ["useridfrom"]=> string(3) "243" ["useridto"]=> string(3) "139" ["message"]=> string(4) "test" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1335517653" ["messagetype"]=> string(6) "direct" } [4]=> array(7) { ["id"]=> string(2) "46" ["useridfrom"]=> string(3) "241" ["useridto"]=> string(3) "139" ["message"]=> string(8) "sdsdfsdf" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336139572" ["messagetype"]=> string(6) "direct" } [5]=> array(7) { ["id"]=> string(2) "47" ["useridfrom"]=> string(3) "241" ["useridto"]=> string(3) "139" ["message"]=> string(13) "8528528285285" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336143958" ["messagetype"]=> string(6) "direct" } array(8) { [6]=> array(7) { ["id"]=> string(2) "52" ["useridfrom"]=> string(3) "330" ["useridto"]=> string(3) "139" ["message"]=> string(10) "test" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336561645" ["messagetype"]=> string(6) "direct" } [7]=> array(7) { ["id"]=> string(2) "53" ["useridfrom"]=> string(3) "330" ["useridto"]=> string(3) "139" ["message"]=> string(8) "bye" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336561648" ["messagetype"]=> string(6) "direct" } [1]=> array(7) { ["id"]=> string(2) "30" ["useridfrom"]=> string(3) "329" ["useridto"]=> string(3) "139" ["message"]=> string(243) "Hi Bob" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1330942044" ["messagetype"]=> string(6) "direct" } [3]=> array(7) { ["id"]=> string(2) "42" ["useridfrom"]=> string(3) "243" ["useridto"]=> string(3) "139" ["message"]=> string(4) "test" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1335517653" ["messagetype"]=> string(6) "direct" } [4]=> array(7) { ["id"]=> string(2) "46" ["useridfrom"]=> string(3) "241" ["useridto"]=> string(3) "139" ["message"]=> string(8) "sdsdfsdf" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336139572" ["messagetype"]=> string(6) "direct" } [5]=> array(7) { ["id"]=> string(2) "47" ["useridfrom"]=> string(3) "241" ["useridto"]=> string(3) "139" ["message"]=> string(13) "8528528285285" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1336143958" ["messagetype"]=> string(6) "direct" } [2]=> array(7) { ["id"]=> string(2) "10" ["useridfrom"]=> string(3) "138" ["useridto"]=> string(3) "139" ["message"]=> string(54) "Hi Emma thank you for submitting your homework - Jenny" ["format"]=> string(1) "0" ["timecreated"]=> string(10) "1309122193" ["messagetype"]=> string(6) "direct" } }

到目前为止，这是我在PHP中所做的事情：

$m = new Messaging(); $json = $m->getUnreadMessages($uid); /** sort messages by useridfrom **/ uasort($json, array($m, 'messageCompare')); foreach($json as $j) { //do sorting of messages here ?? } echo json_encode($json); exit;

我理想地猜测，我想在其中创建一个新数组，其中键是用户形（发送者），然后是他们的消息，然后与时间连接的每个消息相关联。什么是最好的方法？


eDit


您可以从数组示例中看到，有重复的用户从userIdfrom = 241的元素中进行了重复。这意味着用户241已发送了两条消息，如果有3个用户，241个元素，则意味着他/她发送了3条消息。我的目标是将用户从数组中的密钥组合在一起，因此两组将其与该密钥相关联，因此我们都有所有消息（消息）和创建消息的时间（timecreated）。

 [4]=>
  array(7) {
    ["id"]=>
    string(2) "46"
    ["useridfrom"]=>
    string(3) "241"
    ["useridto"]=>
    string(3) "139"
    ["message"]=>
    string(8) "sdsdfsdf"
    ["format"]=>
    string(1) "0"
    ["timecreated"]=>
    string(10) "1336139572"
    ["messagetype"]=>
    string(6) "direct"
  }
  [5]=>
  array(7) {
    ["id"]=>
    string(2) "47"
    ["useridfrom"]=>
    string(3) "241"
    ["useridto"]=>
    string(3) "139"
    ["message"]=>
    string(13) "8528528285285"
    ["format"]=>
    string(1) "0"
    ["timecreated"]=>
    string(10) "1336143958"
    ["messagetype"]=>
    string(6) "direct"
  }

 [1]=>
  array(7) {
    ["id"]=>
    string(2) "30"
    ["useridfrom"]=>
    string(3) "329"
    ["useridto"]=>
    string(3) "139"
    ["message"]=>
    string(243) "Hi Bob"
    ["format"]=>
    string(1) "0"
    ["timecreated"]=>
    string(10) "1330942044"
    ["messagetype"]=>
    string(6) "direct"
  }


因此，从这个示例中，应该导致一系列类似Mariomario所建议的东西：

array{
  ['241'] => array(
   [0] => array(time=>'time1', message => "hello i am 241"),
   [1] => array(time=>'time2', message => "nice to meet you"),
),
['330'] => array(
       [0] => array(time=>'time1', message => "hello i am 330"),
       [1] => array(time=>'time2', message => "goodbye"),
    )
}


    

	
已编辑：



经过一点思考，我会这样做：
$data = array();

foreach ($json as $j) {
    if (!array_key_exists($j['useridfrom'], $data)) {
        $data[$j['useridfrom']] = array();
    }
    if (!array_key_exists($j['useridto'], $data[$j['useridfrom']])) {
        $data[$j['useridfrom']][$j['useridto']] = array();
    }
    $data[$j['useridfrom']][$j['useridto']][] = array(
        'message' => $j['message'],
        'timestamp' => $j['timecreated']  
    );
}



php

arrays

multidimensional-array

grouping


2个回答




    
    
    

        

            

                

                    
2
投票

                    

                

            

        

        
保留订购的数据，然后将所有内容像您想要的订购一样敲击。

this应该净到这样的数组：



ORDER BY timecreated DESC

    


你不会做这样的事情



'sender1' => (
    'recipient1' = (
        (
            'message' => 'MESSAGE HERE',
            'timecreated' => 'TIME HERE'
        ),
        (
            'message' => 'ANOTHER MESSAGE HERE',
            'timecreated' => 'ANOTHER TIME HERE'
        )
    ),
    'recipient2' = (
        (
            'message' => 'MESSAGE HERE',
            'timecreated' => 'TIME HERE'
        )
    )
),
'sender2' => (
)




他们将有这样的数组：



$newArray = array()

foreach($json as $j)
{
 $array[$j['useridfrom']][] = array('time'=>$j['timecreated'],
'message'=>$j[message]);
}

，但也许我理解你不正确。
    

    

    
    
    

    

        

            

                

                    
2
投票

                    
                

            

        

        

php中的Array_multisort使用：



http：//php.net/manual/en/function.array-multisort.php

    

	



    

    


  

  

    
最新问题


  





  

    © www.soinside.com 2019 - 2025. All rights reserved.