什么是最有效的方式,以获得代表当天午夜一个NSDate对象?
尝试这个:
NSDate *const date = NSDate.date;
NSCalendar *const calendar = NSCalendar.currentCalendar;
NSCalendarUnit const preservedComponents = (NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay);
NSDateComponents *const components = [calendar components:preservedComponents fromDate:date];
NSDate *const normalizedDate = [calendar dateFromComponents:components];
NSCalendar *calendar = [NSCalendar currentCalendar];
calendar.timeZone = [NSTimeZone timeZoneWithName:@"UTC"];
NSDate *midnight = [calendar dateBySettingHour:0 minute:0 second:0 ofDate:[NSDate date] options:0];
在iOS的8个新的API
iOS 8的包括上NSCalendar一种新的方法叫做startOfDayForDate,这是很容易使用:
let startOfToday = NSCalendar.currentCalendar().startOfDayForDate(NSDate())
苹果的描述:
此API返回给定日期的前一刻日期。通过在[NSDate的日期],例如,如果你想“今天”的开始。如果有两个午夜,它返回第一个。若不是这样,它返回一个确实存在的第一刻。
更新,关于时区:
由于startOfDayForDate是NSCalendar的方法,它使用NSCalendar的时区。所以,如果我想看看什么时候它是在纽约,当今天开始在洛杉矶,我可以这样做:
let losAngelesCalendar = NSCalendar.currentCalendar().copy() as! NSCalendar
losAngelesCalendar.timeZone = NSTimeZone(name: "America/Los_Angeles")!
let dateTodayBeganInLosAngeles = losAngelesCalendar.startOfDayForDate(NSDate())
dateTodayBeganInLosAngeles.timeIntervalSince1970
let dateFormatter = NSDateFormatter()
dateFormatter.dateStyle = .MediumStyle
dateFormatter.timeStyle = .ShortStyle
dateFormatter.timeZone = NSTimeZone(name: "America/New_York")!
let timeInNewYorkWhenTodayBeganInLosAngeles = dateFormatter.stringFromDate(dateTodayBeganInLosAngeles)
print(timeInNewYorkWhenTodayBeganInLosAngeles) // prints "Jul 29, 2015, 3:00 AM"
NSCalendar *cal = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
[cal setTimeZone:[NSTimeZone systemTimeZone]];
NSDateComponents * comp = [cal components:( NSYearCalendarUnit| NSMonthCalendarUnit | NSDayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit) fromDate:[NSDate date]];
[comp setMinute:0];
[comp setHour:0];
[comp setSecond:0];
NSDate *startOfToday = [cal dateFromComponents:comp];
如果你的意思是午夜23:59然后设置组件的每小时23分钟为59。
你可以用下面的方法来得到一个NSDate午夜值。
- (NSDate *)dateAtBeginningOfDayForDate:(NSDate *)inputDate
{
// Use the user's current calendar and time zone
NSCalendar *calendar = [NSCalendar currentCalendar];
NSTimeZone *timeZone = [NSTimeZone systemTimeZone];
[calendar setTimeZone:timeZone];
// Selectively convert the date components (year, month, day) of the input date
NSDateComponents *dateComps = [calendar components:NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:inputDate];
// Set the time components manually
[dateComps setHour:0];
[dateComps setMinute:0];
[dateComps setSecond:0];
// Convert back
NSDate *beginningOfDay = [calendar dateFromComponents:dateComps];
return beginningOfDay;
}
这是从这里qazxsw POI拍摄。
迅速:
website
雨燕2.2:
let cal = NSCalendar.currentCalendar()
//tip:NSCalendarUnit can be omitted, but with the presence of it, you can take advantage of Xcode's auto-completion
var comps = cal.components(NSCalendarUnit.YearCalendarUnit | .MonthCalendarUnit | .DayCalendarUnit | .HourCalendarUnit | .MinuteCalendarUnit | .SecondCalendarUnit, fromDate: NSDate())
comps.hour = 0
comps.minute = 0
comps.second = 0
let midnightOfToday = cal.dateFromComponents(comps)!
Objective-C的:
let cal = NSCalendar.currentCalendar()
let comps = cal.components([.Year, .Month, .Day, .Hour, .Minute, .Second], fromDate: NSDate())
comps.hour = 0
comps.minute = 0
comps.second = 0
let midnightOfToday = cal.dateFromComponents(comps)!
从iOS8上,你可以使用startDayForDate。
因此,为了得到今天(目标-C)的开头:
NSCalendar *cal = [NSCalendar currentCalendar];
NSDateComponents *comps = [cal components:(NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute) fromDate:[NSDate date]];
[comps setHour:0];
[comps setMinute:0];
[comps setSecond:0];
NSDate *midnightOfToday = [cal dateFromComponents:comps];
尝试这个:
NSDate * midnight;
midnight = [[NSCalendar currentCalendar] startOfDayForDate: [NSDate date]];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *now = [NSDate date];
NSDateComponents *components = [gregorian components:NSDayCalendarUnit | NSMonthCalendarUnit | NSYearCalendarUnit fromDate:now];
NSDateFormatter* df = [[NSDateFormatter alloc]init];
[df setDateFormat:@"MM/dd/yyyy HH:mm:ss.SSS"];
NSLog(@"%@",[df stringFromDate:[gregorian dateFromComponents:components]]);
你可以使用NSCalendar的NSDate *now = [NSDate date];
NSDate *beginningOfToday = nil;
[[NSCalendar currentCalendar] rangeOfUnit:NSDayCalendarUnit startDate:&beginningOfToday interval:NULL forDate:now];
因此,这将是因为这样做很容易:
dateBySettingHour:minute:second:ofDate:options: