以下内容在开发人员控制台中发布为POST:404。我猜我的php不正确。我在这里错了吗?
在这方面,我正在做:
........
user = JSON.stringify(user); // updated Data, want to push to db table blob column
pushData ();
function pushData (){
const ajax = $.ajax({
method: 'POST',
url: `./Settings.php`,
data: {obj_json: JSON.stringify(user) },
dataType: "json",
success: function(result) {
//Write your code here
console.log("data posted?");
}
});
}
.....
( [Settings.php obj_json是在数据库表中设置为blob
的列)。我不太确定该如何处理$obj
class Settingz extends \myApp\Data
{
public function insertBlob($obj, $last_update) {
$obj = $_POST['obj_json'];
$sql = "INSERT INTO MY_TABLE(last_update,obj_json) VALUES(:last_update,:obj_json)";
$stmt = $this->pdo->prepare($sql);
$stmt->bindParam(':last_update', $last_update);
$stmt->bindParam(':obj_json', $blob, PDO::PARAM_LOB);
return $stmt->execute();
}
}
<?php
try {
$db = new PDO('oci:dbname=localhost/orclpdb1', 'cj', 'welcome');
}
catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
exit;
}
$stmt = $db->prepare("drop table cjblob");
$stmt->execute();
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $db->prepare("create table cjblob (id number, data blob)");
$stmt->execute();
function do_insert($db, $id, $data)
{
$stmt = $db->prepare("insert into cjblob (id, data) values (:id, empty_blob()) returning data into :blob");
$stmt->bindParam(':id', $id);
$stmt->bindParam(':blob', $blob, PDO::PARAM_LOB);
$blob = null;
$db->beginTransaction();
$stmt->execute();
// var_dump($blob); // $blob becomes a stream
fwrite($blob, $data);
fclose($blob);
$db->commit();
}
do_insert($db, 1, str_pad("Z", 40000, "Z"));
// Fetch it back
$stmt = $db->prepare('select data from cjblob where id = ?');
$id = 1;
$stmt->execute(array($id));
$row = $stmt->fetch(PDO::FETCH_ASSOC);
var_dump($row);
var_dump(stream_get_contents($row['DATA']));
?>