用具有逻辑 &&(AND) 运算符的单个 IF 语句替换嵌套 IF 语句以实现相同的输出

Question

美好的一天！

下面是演示考试分数的嵌套 IF 语句的代码：

公共类 NestIfExample {

public static void main(String[] args) {
    
    Scanner inputDevice = new Scanner(System.in);
    
    // Asking the user to input their score
    System.out.print("Enter your score: ");
    int score = inputDevice.nextInt();

    // Outer if statement
    if (score >= 50) {
        System.out.println("You passed the exam!");

        // Inner if statement - only checked if the score is 50 or more
        if (score >= 80) {
            System.out.println("Great job! You scored in the top range.");
        } else {
            System.out.println("Good effort, but there's room for improvement.");
        }
    } else {
        System.out.println("Unfortunately, you did not pass. Try again next time.");
    }
}

}

如何将此嵌套 IF 语句更改为具有逻辑 &&(AND) 运算符的单个 IF 语句并获得相同的输出？

这是我尝试过的。我通过连接两个条件并使它们成为一个条件（分数 >= 80 && 分数 >= 50）创建了一个 SINGLE IF 语句。 我不确定这是否正确。请告诉我。

public static void main(String[] args) { 扫描仪输入设备 = new Scanner(System.in);

    // Asking the user to input their score
    System.out.print("Enter your score: ");
    int score = inputDevice.nextInt();

    // Single if statement using logical AND (&&) operator
    if (score >= 80 && score >= 50) {
        System.out.println("You passed the exam!");
        System.out.println("Great job! You scored in the top range.");
    } else if (score >= 50) {
        System.out.println("You passed the exam!");
    } else {
        System.out.println("Unfortunately, you did not pass. Try again next time.");
    }
}

}

Answer 1

你已经很接近了，但是你错过了第二个条件的打印语句：

// Asking the user to input their score
System.out.print("Enter your score: ");
int score = inputDevice.nextInt();

// Single if statement using logical AND (&&) operator
if (score >= 80 && score >= 50) {
    System.out.println("You passed the exam!");
    System.out.println("Great job! You scored in the top range.");
} else if (score >= 50) {  // implicit: score < 80 for this case
    System.out.println("You passed the exam!");
    // only change is next line
    System.out.println("Good effort, but there's room for improvement.");
} else {
    System.out.println("Unfortunately, you did not pass. Try again next time.");
}