我尝试通过jframe和Jtext插入查询,但出现此错误:com.microsoft.sqlserver.jdbc.SQLServerException:无效的列名“ A”。(我插入值名称= A,城市= B,街道= c,电话= 0542223)
private static final String SQL2 = "insert into Hospital (name,city,street,phone) values (";
private static final String CONN_URL = "jdbc:sqlserver://localhost:1433;databaseName=MedicalDB;integratedSecurity=true;";
JLabel name = new JLabel("name");
JTextField name1 = new JTextField();
name1.setPreferredSize(new Dimension(100, 30));
JLabel city = new JLabel("city");
JTextField city1 = new JTextField();
city1.setPreferredSize(new Dimension(100, 30));
JLabel street3 = new JLabel("the street");
JTextField street4 = new JTextField();
street4.setPreferredSize(new Dimension(100, 30));
JLabel Phone = new JLabel("Phone num");
JTextField Phone1 = new JTextField();
Phone1.setPreferredSize(new Dimension(100, 30));
String name = name1.getText();
String city = city1.getText();
String street = street4.getText();
String phone = Phone1.getText();
Statement stmt1 = con.createStatement();
System.out.println(phone);
String theString = SQL2 + name + "," + city + "," + street +"," + phone + ");";
stmt1.executeUpdate(theString);
}
catch (Exception e1) {
e1.printStackTrace();
System.out.println("here5");
}
}
您没有引用要插入的字符串变量,因此数据库将它们解释为列名,然后由于这些列不存在而失败。
避免这种问题和SQL注入攻击漏洞的教科书方法是使用PreparedStatement
:
PreparedStatement
经过更多检查后,我发现了:我刚刚从以下位置更改了代码:
private static final String INSERT_SQL =
"insert into Hospital (name, city, street, phone) values (?, ?, ?, ?)";
try (ps = con.prepareStatement(INSERT_SQL)) {
ps.setString(1, name);
ps.setString(2, city);
ps.setString(3, street);
ps.setString(4, phone);
ps.executeUpdate();
}
至:
String theString = SQL2 + name + "," + city + "," + street +"," + phone + ");";