列的练习值

Question

Member

campaign2006

	1
1	2007
1	2008
2	2023
2	2024
	这个

Member

campaign

pastcampaigns

120062006120072006,2007120082006,2007,2008220232023220242023,2024 非常感谢您的帮助。 我试图在各种论坛上寻找一些解决方案，但找不到任何具体的解决方案。 ROW_NUMBER()的帮助下通过自我加入方法来处理这一点：

任何想法？		我们可以在

WITH cte AS (
    SELECT *, ROW_NUMBER() OVER (PARTITION BY Member ORDER BY Campaign) rn
    FROM yourTable

)

SELECT
    t1.Member,
    t1.Campaign,
    LISTAGG(t2.Campaign) WITHIN GROUP (ORDER BY t2.Campaign) Pastcampaigns
FROM cte t1
INNER JOIN cte t2
    ON t2.Member = t1.Member AND
       t2.Campaign <= t1.Campaign
GROUP BY
    t1.Member,
    t1.Campaign
ORDER BY
    t1.Member,
    t1.Campaign;

调用为每个成员中的每个活动添加了一个序列。 然后，自结合的技巧将每一行与以前的坎皮金有关。 然后，我们通过成员和广告系列汇总以生成先前广告系列的CSV列表。 demo

演示在MySQL中，但逻辑和数据与雪花相同。

Answer 1

基于评论中提到的方法使用

ROW_NUMBER()

和

ARRAY_AGG

.

。

样本查询

ARRAY_TO_STRING

将其拆下来

SELECT 
    member, 
    campaign,
    ARRAY_TO_STRING(ARRAY_AGG(campaign) OVER ( 
    PARTITION BY member ORDER BY campaign  ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW), ',') AS past_campaigns
FROM campaigns
ORDER BY member, campaign;

组类似成员（PARTITION BY member ORDER BY campaign ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW ）

基于活动（

PARTITION BY member

）

Answer 2

ORDER BY campaign

）

然后，将广告系列组合到数组中，然后

array_to_string

将数组转换为带有逗号分离值的字符串。

输出