PHP Code:
<td>
<div class="dropdown">
<button class="btn btn-warning dropdown-toggle" type="button" id="dropdownMenuButton" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
More
</button>
<div class="dropdown-menu" aria-labelledby="dropdownMenuButton" id="demolist">
<a class="dropdown-item " id="achieve" value="<?php echo $value['user_login_id'] ?>">Achivements</a>
<a class="dropdown-item" id="skill" value="<?php echo $value['user_login_id'] ?>">Skills</a>
<!--<a class="dropdown-item">Remove</a>
<a class="dropdown-item">View Applicant</a>-->
</div>
</div>
</td>
这里每个行都有这个下拉按钮,每个按钮都有其成就和技能列表。特定行成就的onclick,我想传递该行的ID或Ajax,我应该如何发送我努力与jQuery。谁能给我解决一个jQuery代码
使用此方法,您可以轻松获得下拉值: