如何使用期货“ 0.3”和超级“ 0.13.0-alpha.4”编写一个简单的Rust异步代理?

问题描述 投票:3回答:1

我正试图通过迁移到:]来重写example书的代理Asynchronous Programming in Rust。>

futures-preview = { version = "0.3.0-alpha.19", features = ["async-await"]}`
hyper = "0.13.0-alpha.4"`

来自:

futures-preview = { version = "=0.3.0-alpha.17", features = ["compat"] }`
hyper = "0.12.9"

当前示例将返回的Futurefutures 0.3转换为futures 0.1,因为hyper = "0.12.9"futures 0.3的异步/等待不兼容。

我的代码:

use {
    futures::future::{FutureExt, TryFutureExt},
    hyper::{
        rt::run,
        service::{make_service_fn, service_fn},
        Body, Client, Error, Request, Response, Server, Uri,
    },
    std::net::SocketAddr,
    std::str::FromStr,
};

fn forward_uri<B>(forward_url: &'static str, req: &Request<B>) -> Uri {
    let forward_uri = match req.uri().query() {
        Some(query) => format!("{}{}?{}", forward_url, req.uri().path(), query),
        None => format!("{}{}", forward_url, req.uri().path()),
    };

    Uri::from_str(forward_uri.as_str()).unwrap()
}

async fn call(
    forward_url: &'static str,
    mut _req: Request<Body>,
) -> Result<Response<Body>, hyper::Error> {
    *_req.uri_mut() = forward_uri(forward_url, &_req);
    let url_str = forward_uri(forward_url, &_req);
    let res = Client::new().get(url_str).await;
    res
}

async fn run_server(forward_url: &'static str, addr: SocketAddr) {
    let forwarded_url = forward_url;
    let serve_future = service_fn(move |req| call(forwarded_url, req).boxed());

    let server = Server::bind(&addr).serve(serve_future);
    if let Err(err) = server.await {
        eprintln!("server error: {}", err);
    }
}

fn main() {
    // Set the address to run our socket on.
    let addr = SocketAddr::from(([127, 0, 0, 1], 3000));
    let url = "http://127.0.0.1:9061";
    let futures_03_future = run_server(url, addr);
    run(futures_03_future);
}

首先,我在server函数中收到有关run_server的错误:

特征tower_service::Service<&'a hyper::server::tcp::addr_stream::AddrStream>未实现hyper::service::service::ServiceFn<[closure@src/main.rs:35:35: 35:78 forwarded_url:_], hyper::body::body::Body>

而且,我不能使用hyper::rt::run,因为它可能在hyper = 0.13.0-alpha.4中以不同的方式实现。

如果您告诉我您如何解决它的想法,我将不胜感激。

我正在尝试通过迁移到以下脚本来重写Rust本书中的异步编程的代理示例:futures-preview = {version =“ 0.3.0-alpha.19”,features = [“ async-await”]}`hyper = “ 0.13.0-alpha ....

asynchronous proxy rust async-await hyper
1个回答
1
投票

通过此issue,要为每个连接创建新服务,您需要在MakeService中创建hyper = "0.13.0-alpha.4"。您可以使用MakeService创建带闭合的make_service_fn

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