是否可以使用 boost 预处理器 API 在函数中传递结构体的所有成员 我有类似的东西,但无法编译。
#include <iostream>
#include <boost/preprocessor/cat.hpp>
#include <boost/preprocessor/seq/for_each.hpp>
#include <boost/preprocessor/seq/variadic_seq_to_seq.hpp>
#include <boost/preprocessor/seq/elem.hpp>
// Define a macro to generate code for passing a struct member to a function
#define PASS_MEMBER_TO_FUNCTION(r, structName, elem) \
function(BOOST_PP_SEQ_ELEM(0, elem), structName.BOOST_PP_SEQ_ELEM(1, elem));
// Define a macro to iterate over struct members and pass them to a function
#define PASS_MEMBERS_TO_FUNCTION(structName, members) \
BOOST_PP_SEQ_FOR_EACH(PASS_MEMBER_TO_FUNCTION, structName, BOOST_PP_VARIADIC_SEQ_TO_SEQ(members))
// Example struct
struct MyStruct {
int height;
double width;
const char* name;
};
// Example function that takes struct members
void function(int value, double width, const char* name) {
// Your function implementation here
std::cout << "Value: " << value << ", Width: " << width << ", Name: " << name << std::endl;
}
int main() {
// Usage example
MyStruct myStruct{10, 20.5, "example"};
PASS_MEMBERS_TO_FUNCTION(myStruct, ((int, height))((double, width))((const char*, name)));
return 0;
}
使用 Boost PFR,您不需要预处理器:
std::apply(function, boost::pfr::structure_tie(myStruct));
演示 在 Coliru 上直播:
#include <boost/pfr.hpp>
#include <iostream>
struct MyStruct {
int height;
double width;
char const* name;
};
// Example function that takes separate parameters
void function(int value, double width, char const* name) {
std::cout << "Value: " << value << ", Width: " << width << ", Name: " << name << std::endl;
}
int main() {
// Usage example
MyStruct myStruct{10, 20.5, "example"};
apply(function, boost::pfr::structure_tie(myStruct));
}
印刷
Value: 10, Width: 20.5, Name: example