对嵌套字典进行排序

Question

我想根据分数对这个字典中的团队进行排序，并且我已经遵循了这篇post中的建议 我编写的排序代码无法按我想要的方式工作，

这是我的字典：

{
    'Spain': {
        'wins': 3,
        'loses': 0,
        'draws': 0,
        'goal difference': 4,
        'points': 9
    },
    'Iran': {
        'wins': 0,
        'loses': 3,
        'draws': 0,
        'goal difference': -6,
        'points': 0
    },
    'Portugal': {
        'wins': 2,
        'loses': 1,
        'draws': 0,
        'goal difference': 4,
        'points': 6
    },
    'Morocco': {
        'wins': 1,
        'loses': 2,
        'draws': 0,
        'goal difference': -2,
        'points': 3
    }
}

以及我用于排序的代码：

sorted_dict = OrderedDict(sorted(B_group.items(),key= lambda x:  x[1]["points"] ,reverse=True))

这是我得到的结果：

Spain  wins:3 , loses:0 , draws:0 , goal difference:4 , points:9
Iran  wins:0 , loses:3 , draws:0 , goal difference:-6 , points:0
Portugal  wins:2 , loses:1 , draws:0 , goal difference:4 , points:6
Morocco  wins:1 , loses:2 , draws:0 , goal difference:-2 , points:3

我希望将积分最高的球队放在第一位，例如西班牙、葡萄牙、摩洛哥、伊朗在此列表中， 我写的排序代码有问题吗？

Answer 1

您不再需要使用

OrderedDict

。

dict

目前正在维护插入顺序。

试试这个：

d = {
    "Spain": {"wins": 3, "loses": 0, "draws": 0, "goal difference": 4, "points": 9},
    "Iran": {"wins": 0, "loses": 3, "draws": 0, "goal difference": -6, "points": 0},
    "Portugal": {"wins": 2, "loses": 1, "draws": 0, "goal difference": 4, "points": 6},
    "Morocco": {"wins": 1, "loses": 2, "draws": 0, "goal difference": -2, "points": 3},
}

sorted_d = dict(sorted(d.items(), key=lambda x: x[1]["points"], reverse=True))
print(sorted_d)

输出：

{'Spain': {'wins': 3, 'loses': 0, 'draws': 0, 'goal difference': 4, 'points': 9}, 'Portugal': {'wins': 2, 'loses': 1, 'draws': 0, 'goal difference': 4, 'points': 6}, 'Morocco': {'wins': 1, 'loses': 2, 'draws': 0, 'goal difference': -2, 'points': 3}, 'Iran': {'wins': 0, 'loses': 3, 'draws': 0, 'goal difference': -6, 'points': 0}}