你好,我做了深层副本,而浅层副本是由用户AndyMan建议的,现在我做了JUnit,我在进行这些测试时遇到了一些小问题:
1。深拷贝方法
public ListNode<E> deep_clone() {
first = deep_clone(first);
ListNode<E> copy = new ListNode<>(first);
return copy;
}
private static Node deep_clone(Node head) {
if (head == null) {
return null;
}
Node temp = new Node(head.getData());
temp.setNext(deep_clone(head.getNext()));
return temp;
}
编辑
非常感谢AndyMan提出了这种浅表复制方法:
private static Node shallow_clone(Node head) {
if (head == null)
return null;
Node temp = new Node(head.getData());
temp.setNext(head.getNext()); // Just copy the reference
return temp;
}
但是有一个问题,如何同时Junit
深层复制和浅层复制方法?
我做了以下操作,但Junit测试失败:
@Test
public void test_shallow_clone(){
ListNode<Integer> list =new ListNode<>();
for (int i = 0; i < 10; i++)
list.insert(i);
ListNode<Integer>cloned =list.shallow_clone();
//assertSame(cloned,list); //failed i dont know why
//assertEquals(cloned, list);//Even though its shallow copy i get that they are not equal!
assertSame(list.getFirst(), cloned.getFirst());
assertTrue(cloned.equals(list));
}
以及深层副本的测试:
@Test
public void test_depp_clone(){
ListNode<Integer> list =new ListNode<>();
for (int i = 0; i < 10; i++)
list.insert(i);
ListNode<Integer>cloned =list.depp_clone();
assertSame(cloned.getFirst(),list.getFirst());//check for same val..
//assertEquals(cloned, list);//this make the test fail..
assertFalse(cloned.equals(list));//okay the are not equal lists this means its deep copy...no implemented equal method :)
}
class ListNode
public class ListNode<E> implements Iterable<E>{
private Node<E> first;
//private Node<E> last;
public ListNode() {
first = null;
//last = null;
}
public ListNode(Node head) {
this.first = head;
//this.last = this.first;
}
public ListNode(E data) {
Node head = new Node(data);
this.first = head;
//this.last = this.first;
}
@Override
public Iterator<E> iterator() {
return new LL_Iterator<>(first);
}
private static class Node<E> {
private E data;
private Node next;
public Node() {
this.data = null;
this.next = null;
}
public Node(E data) {
this.data = data;
next = null;
}
public Node(E data, Node next) {
this.data = data;
this.next = null;
}
public E getData() {
return data;
}
public void setData(E val) {
this.data = val;
}
public Node getNext() {
return next;
}
public void setNext(Node next) {
this.next = next;
}
@Override
public String toString() {
return "Node{" + "data=" + data + ", next=" + next + '}';
}
}
private static class LL_Iterator<E> implements Iterator<E> {
private Node<E> curr;//we have to specify the E here because if we dont we have to cast the curr.getData()
public LL_Iterator(Node head) {
curr = head;
}
@Override
public boolean hasNext() {
return curr != null;
}
@Override
public E next() {
if (hasNext()) {
E data = curr.getData();
curr = curr.getNext();
return data;
}
return null;
}
}
public E getFirst(){
if(first==null)
return null;
return first.getData();
}
public boolean addFirst (E data) {
if(data==null)
return false;
Node t= new Node (data);
t.setNext(first);
first=t;
return true;
}
public E getLast() {
if (first==null)
return null;
return getLast(first).getData();
}
private static<E> Node<E> getLast(Node<E> head) {
if (head == null) {
return null;
}
Node temp = head;
if (temp.getNext() != null) {
temp = getLast(temp.getNext());
}
return temp;
}
//insertion....Wie setLast
public boolean insert(E data) {
if(data==null)
return false;
first = insert(first, data);
//last = getLast();
return true;
}
private static <E> Node insert(Node head, E data) {
if (head == null) {
return new Node(data);
} else {
head.setNext(insert(head.getNext(), data));
}
return head;
}
public void printList(){
LL_Iterator it= new LL_Iterator(first);
printUsingIterator(it,it.next());
}
private static<E> void printUsingIterator (LL_Iterator it, E data){
//VERDAMMT MAL RHEINFOLGE DER ANWEISUNGEN MACHT UNTERSCHIED
System.out.print(data+"->");
if (!it.hasNext()) {
System.out.print(it.next()+"\n");//THIS WILL PRINT NULL!!!
return;
}
printUsingIterator(it,it.next());
}
public int size() {
return size(first);
}
private static int size(Node head) {
if (head == null) {
return 0;
} else {
return 1 + size(head.getNext());
}
}
public boolean contains(E data) {
return contains(first, data);
}
public static <E> boolean contains(Node head, E data) {
if (head == null || data == null) {
return false;
}
if (head.getData().equals(data)) {
return true;
}
return contains(head.getNext(), data);
}
public int countIf(E t) {
return countIf(first, t);
}
private static <E> int countIf(Node head, E t) {
if (head == null ||t ==null) {
return 0;
}
if (head.getData().equals(t)) {
return 1 + countIf(head.getNext(), t);
}
return countIf(head.getNext(), t);
}
//TODO: WHY IM GETTING HERE AN OVERRIDE REQUEST FROM THE COMPILER??
//answer because im overriding the damn clone() of the list class which is shallow clone
public ListNode<E> depp_clone() {
first = depp_clone(first);
ListNode<E> copy = new ListNode<>(first);
return copy;
}
private static Node depp_clone(Node head) {
if (head == null) {
return null;
}
Node temp = new Node(head.getData());
temp.setNext(depp_clone(head.getNext()));
return temp;
}
public ListNode shallow_clone (){
ListNode<E> cloned=new ListNode<>(shallow_clone(first));
return cloned;
}
private static Node shallow_clone(Node head) {
if (head == null)
return null;
Node temp = new Node(head.getData());
temp.setNext(head.getNext()); // Just copy the reference
return temp;
}
在深层副本中,创建两个新节点7和8:deepCopy = node7 => node6
在浅表副本中,创建一个新节点7并将引用复制到原始节点:allowCopy = node7 => node1
private static Node shallow_clone(Node head) {
if (head == null) {
return null;
}
Node temp = new Node(head.getData());
temp.setNext(head.getNext()); // Just copy the reference
return temp;
}如果原始node1被更改,它将同时影响原始副本和浅副本。它不会影响深层副本。
现在是术语。已经描述了如何深度复制或浅复制节点。
浅表复制链表实际上没有意义,因为您实际上只是浅表一个节点。当然,您可以复制列表。
如果是数组而不是链接列表,则可以进行浅拷贝或深拷贝。要测试这些,请覆盖equals()和hashCode()。如果两个列表具有相同的值,我会认为它们相等。为了使两个节点相等,它们应具有相同的值,并且列表的其余部分应相等。如果不重写equals(),则使用Object中的实现。对象使用按位比较需要相同的引用。您可能需要查找一下。
同样,当覆盖equals()时,也需要覆盖hashCode()。这与问题没有直接关系,因此您可能需要照看它。
ListNode equals()和hashCode()
:@Override public boolean equals(Object otherObject) { // Objects are equal if they have the same value, and next has the same value if (otherObject instanceof ListNode) { ListNode other = (ListNode)otherObject; return first.equals(other.first); } else { return false; } } @Override public int hashCode() { return first.hashCode(); }
节点equals()和hashCode():
@Override public boolean equals(Object otherObject) { // Objects are equal if they have the same value, && next has the same value if (otherObject instanceof Node) { Node other = (Node)otherObject; return data.equals(other.data) && ((next == null && ((Node) otherObject).getNext() == null) || next.equals(((Node) otherObject).next)); } else { return false; } } @Override public int hashCode() { return data.hashCode(); }