import argparse
class customAction(argparse.Action):
def __call__(self, parser, args, values, option_string=None):
setattr(args, self.dest, values)
parser = argparse.ArgumentParser()
parser.add_argument('-e', '--example', action=customAction)
我想在触发选项 -e 时将附加参数传递给 customAction,例如另一个类的实例。我怎样才能做到这一点?我尝试过的一切都出错了。
def make_action(additional_arg):
class customAction(argparse.Action):
def __call__(self, parser, args, values, option_string=None):
print(additional_arg)
setattr(args, self.dest, values)
return customAction
#...
parser.add_argument('-e', '--example', action=make_action('your arg'))
另一种解决方案是派生基类
argparse.Action
,如下所示:
class CustomAction(argparse.Action):
def __init__(self,option_strings,
additional_arg1,additional_arg2,
dest=None,
nargs=0,
default=None,
required=False,
type=None,
metavar=None,
help=None):
self._a1=additional_arg1
self._a2=additional_arg2
super(CustomAction, self).__init__(
option_strings=option_strings,
dest=dest,
nargs=nargs,
default=default,
required=required,
metavar=metavar,
type=type,
help=help)
def __call__(self, parser, namespace, values, option_string=None):
print(self._a1)
print(self._a2)
setattr(namespace, self.dest, values)
#........
parser.add_argument('-e', '--example', action=CustomAction, additional_arg1='your arg', additional_arg2=42)
或者,提供
*args
和 **kwargs
将任何其他参数传递给父构造函数。
class CustomAction(argparse.Action):
def __init__(self, option_strings, additional_arg1, additional_arg2,
*args, **kwargs):
self._a1 = additional_arg1
self._a2 = additional_arg2
super(CustomAction, self).__init__(option_strings=option_strings,
*args, **kwargs)
def __call__(self, parser, namespace, values, option_string=None):
print(self._a1)
print(self._a2)
setattr(namespace, self.dest, values)
#........
parser.add_argument('-e', '--example', action=CustomAction, additional_arg1='your arg', additional_arg2=42)