Random.Randint（）重复

Question

我有这个游戏，你需要对从列表发送的5个随机表情符号做出反应。问题是有时random.randint()吐出相同的表情符号两次，所以它不可能对相同的表情符号反应两次同样的表情符号。有没有更好的方法来做多个random.randints？

async def food_loop():
    await client.wait_until_ready()
    channel = client.get_channel("523262029440483329")
    while not client.is_closed:
        foodtime = random.randint(1440, 1880)
        food = ['🍇','🍈','🍉','🍊','🍋','🍌','🍍','🍎','🍏','🍐','🍑','🍒','🍓','🥝','🍅','🥑','🍆','🥔','🥕','🌽','🌶',
                '🥒','🍄','🥜','🌰','🍞','🥐','🥖','🥞','🧀','🍖','🍗','🥓','🍔','🍟','🍕','🌭','🌮','🌯',
                '🥙','🍳','🥘','🍲','🥗','🍿','🍱','🍘','🍙','🍚','🍛','🍜','🍝','🍠','🍢','🍣','🍤','🍥','🍡',
                '🍦','🍧','🍨','🍩','🍪','🎂','🍰','🍫','🍬','🍭','🍮','🥛','☕','🍵','🍶','🍾','🍷','🍸','🍹','🍺',
                '🥃']
        food1 = food[random.randint(0,79)]
        food2 = food[random.randint(0,79)]
        food3 = food[random.randint(0,79)]
        food4 = food[random.randint(0,79)]
        food5 = food[random.randint(0,79)]
        foodmonies = random.randint(350,750)
        up = 'order up'
        def orderup(m):
            return m.content.lower() == up
        foodmsg = 'Customer has ordered {}, {}, {}, {}, and {}! Fulfill their order ASAP!'.format(food1, food2, food3, food4, food5)
        foodmsgsend = await client.send_message(channel, foodmsg)
        foodpay1 = await client.wait_for_reaction(emoji=food1, message=foodmsgsend, timeout=3600,
                                             check=lambda reaction, user: user != client.user)
        foodpay2 = await client.wait_for_reaction(emoji=food2, message=foodmsgsend, timeout=3600,
                                             check=lambda reaction, user: user != client.user)
        foodpay3 = await client.wait_for_reaction(emoji=food3, message=foodmsgsend, timeout=3600,
                                             check=lambda reaction, user: user != client.user)
        foodpay4 = await client.wait_for_reaction(emoji=food4, message=foodmsgsend, timeout=3600,
                                             check=lambda reaction, user: user != client.user)
        foodpay5 = await client.wait_for_reaction(emoji=food5, message=foodmsgsend, timeout=3600,
                                             check=lambda reaction, user: user != client.user)
        foodguess = await client.wait_for_message(timeout=3600, channel=channel, check=orderup)
        if foodpay1 and foodpay2 and foodpay3 and foodpay4 and foodpay5 and foodpay3.user.id in blacklist:
            pass
        else:
            if foodpay1 and foodpay2 and foodpay3 and foodpay4 and foodpay5 and foodguess:
                await client.delete_message(foodmsgsend)
                await client.send_message(channel, "{} fulfills the order and earns ${}".format(foodpay5.user.mention, foodmonies))
                add_dollars(foodpay5.user, foodmonies)
                await asyncio.sleep(int(foodtime))

Answer 1

根据定义，随机数可以是重复的，因为对randint的任何调用都与前一个无关。您可以替换以下内容：

food1 = food[random.randint(0,79)]
food2 = food[random.randint(0,79)]
food3 = food[random.randint(0,79)]
food4 = food[random.randint(0,79)]
food5 = food[random.randint(0,79)]

有了这个：

food1, food2, food3, food4, food5 = random.sample(food, 5)

来自docs（强调我的）：

random.sample(population, k)

返回从总体序列或集合中选择的k长度的唯一元素列表。

话虽这么说，重构那个部分并切换到使用列表而不是声明5个变量是一个更好的主意（如果你需要50或500，它会更加混乱）。