-locals（）奇怪的行为python？

Question

为什么这不起作用？

    Python 3.11.6 (main, Oct  8 2023, 05:06:43) [GCC 13.2.0] on linux
    Type "help", "copyright", "credits" or "license" for more information.
    condition ={'RAPPORT': 1, 'COMPA': 0.815, 'varie': 'N_GRAIN'}
    N_GRAIN, RAPPORT, COMPA, ACC, FREQ = 0.,0.,0.,0.,0.
    print(locals()['RAPPORT'])
    0.0
    match = all(condition[key] == locals()[key] for key in condition if key != 'varie')

    Traceback (most recent call last):
    File "<stdin>", line 1, in <module>
    File "<stdin>", line 1, in <genexpr>
    KeyError: 'RAPPORT'

我不明白为什么它给了我一个钥匙扣，因为“融洽关系”处于状态，在当地人（）！？

I在Python2上重现了它，但具有不同的键错误。这是代码：

    Python 2.7.18 (default, Oct 15 2023, 16:43:11)
    [GCC 11.4.0] on linux2

    Type "help", "copyright", "credits" or "license" for more information.
    condition ={'RAPPORT': 1, 'COMPA': 0.815, 'varie': 'N_GRAIN'}
    N_GRAIN, RAPPORT, COMPA, ACC, FREQ = 0.,0.,0.,0.,0.
    print(locals()['RAPPORT'])
    0.0
    match = all(condition[key] == locals()[key] for key in condition if key != 'varie')
    Traceback (most recent call last):
    File "<stdin>", line 1, in <module>
    File "<stdin>", line 1, in <genexpr>
    KeyError: 'COMPA'

您的发电机创建了一个新的范围，以使当地人（）现在与外部范围不同。 您可以通过以下方式解决此问题：

Answer 1

condition = {"RAPPORT": 1, "COMPA": 0.815, "varie": "N_GRAIN"}
N_GRAIN, RAPPORT, COMPA, ACC, FREQ = 0.0, 0.0, 0.0, 0.0, 0.0
locals_ = locals()
all(condition[key] == locals_[key] for key in condition.keys() if key != 'varie')