尝试使用 HttpUrlConnection 在 Java 中查询 api 时出现以下错误:
"Exception in thread "main" java.lang.IllegalArgumentException: Illegal character(s) in message header value: Basic MTk2YTVjODdhNWI2YjFmNWE3ZmQ5ODEtYjFjYTEzZmUtM2FkNC0xMWU1LWEyZjAtMDBkMGZlYTgy
NjI0OmY3NDQ2ZWQ0YjhjNzI2MzkyMzY1YzczLWIxY2ExNjQ4LTNhZDQtMTFlNS1hMmYwLTAwZDBm
ZWE4MjYyNA=="
这是我的代码:
public class LocalyticsTest {
public static void main(String[] args) throws UnsupportedEncodingException {
String apiKey = "MyKey";
String apiSecret = "MySecretKey";
String apiUrl = "https://api.localytics.com/v1/query";
String credentials = apiKey + ":" + apiSecret;
//String encoding = Base64.encode(apiKey.getBytes("UTF-8"));
//String encoding2 = Base64.encode(apiSecret.getBytes("UTF-8"));
String encoding3 = new sun.misc.BASE64Encoder().encode (credentials.getBytes("UTF-8"));
String appId = "myAppId";
String metric = "sessions";
String dimensions = "day";
String condition = "'{\"day\":[\"between\",\"'.$newDate.'\",\"'.$newDate.'\"]}'";
Map data = new HashMap();
data.put("app_id", appId);
data.put("metric", metric);
data.put("dimensions", dimensions);
data.put("condition", condition);
QueryEncoder q = new QueryEncoder();
String newData = q.toQueryString(data);
String newUrl = String.format("%s?%s", apiUrl, newData);
try{
URL url = new URL(newUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
//conn.setRequestMethod("GET");
//conn.setRequestProperty("Authorization", "Basic");
//conn.setRequestProperty(apiKey,apiSecret);
conn.setRequestProperty("Authorization", "Basic " + encoding3);
conn.setRequestProperty("Accept", "application/vnd.localytics.v1+hal+json");
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
我可以使用 Curl 使其在 php 中正常工作,如下所示:
function call_localytics_api($method, $url, $data)
{
$curl = curl_init();
$url = sprintf("%s?%s", $url, http_build_query($data));
$api_key = "myKey";
$api_secret = "mySecret";
// Optional Authentication:
curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_BASIC);
curl_setopt($curl, CURLOPT_USERPWD, $api_key . ":" . $api_secret);
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
// Disable the SSL verificaiton process
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($curl, CURLOPT_HTTPHEADER, array("Accept: application/vnd.localytics.v1+hal+json"));
// Confirm cURL gave a result, if not, write the error
$response = curl_exec($curl);
if ($response === FALSE) {
die("Curl Failed: " . curl_error($curl));
} else {
return $response;
}
}
$api_querystring = "https://api.localytics.com/v1/query";
$app_id = "myAppId";
$metric = "sessions";
$dimensions = "day";
//$data = array(app_id => $app_id, metrics => $metric, dimensions => $dimensions, conditions => '{"day":["in","'.$requestDate.'"]}');
$data = array(app_id => $app_id, metrics => $metric, dimensions => $dimensions, conditions => '{"day":["between","'.$newDate.'","'.$newDate.'"]}');
$response = call_localytics_api('GET', $api_querystring, $data);
$json = json_decode($response);
print_r($json);
只需要帮助让它在 Java 中工作。
看来非法字符是换行符。 使用不会在结果中添加换行符的 Base 64 编码器,或者自行删除换行符。
从 Java 8 开始,您应该使用:
String encoding3 = Base64.getEncoder().encodeToString(
credentials.getBytes(StandardCharsets.UTF_8));
在旧版本的 Java 中,您可以使用 DatatypeConverter:
String encoding3 = DatatypeConverter.printBase64Binary(
credentials.getBytes(StandardCharsets.UTF_8));
您也可以直接删除换行符,但您应该使用上述方法之一。 sun.* 类不供开发使用,它们可能会从一个 Java 版本到下一版本发生更改或消失。 此外,据我了解,由于模块限制,从 Java 9 开始,无论它们是否存在,它们甚至可能根本无法使用。
确保在编码为 Base64 时没有分块
org.apache.commons.net.util.Base64.encodeBase64String(texst.getBytes(), false);