在单个可绘图形python上绘制多条线

Question

如何在不必重复添加“ fig.add_trace”的情况下在同一图形上绘制所有10个图形？

import plotly.graph_objects as go

# Create random data with numpy
import numpy as np

random_x = np.linspace(0, 499, 500)

output = np.vstack([random.sample(range(0, 40), 40) for x in range(10)])


# Create traces
fig = go.Figure()
fig.add_trace(go.Scatter(x=random_x, y=output[1,:],
                         line=dict(color='Blue'),
                         mode='lines', 
                         name='position 0'))

fig.add_trace(go.Scatter(x=random_x, y=output[2,:],
                         line=dict(color='Blue'),
                         mode='lines', 
                         name='position 2'))

fig.add_trace(go.Scatter(x=random_x, y=output[3,:],
                         line=dict(color='Green'),
                         mode='lines', 
                         name='position 3'))

fig.add_trace(go.Scatter(x=random_x, y=output[4,:],
                         line=dict(color='Red'),
                         mode='lines', 
                         name='position 4'))

fig.show()

上面的代码在绘图上显示4条线

Answer 1

我刚刚添加了一个for循环。

import random
# Create random data with numpy
import numpy as np
random_x = np.linspace(0, 499, 500)
output = np.vstack([random.sample(range(0, 40), 40) for x in range(10)])


# Create traces
fig = go.Figure()
# Increase this to 10 colours
color  = ['Blue', 'Red', 'Green', 'Yellow', 'Black', 'Grey']

for i in range(6):
    fig.add_trace(go.Scatter(x=random_x, y=output[i+1,:],
                             line=dict(color=color[i]),
                             mode='lines',
                             name='position' + str(i)))


fig.show()