如何通过多个值在迅速通知

Question

如何通过通知发送串号及一个...

let mynumber=1;
let mytext="mytext";
NSNotificationCenter.defaultCenter().postNotificationName("refresh", object: ?????????????);

并接收在接收器中的值？

func refreshList(notification: NSNotification){
        let receivednumber=??????????
        let receivedString=?????????
    }

Answer 1

你可以在NSArray或NSDictionary或自定义对象将它们包装。

例如：

let mynumber=1;
let mytext="mytext";

let myDict = [ "number": mynumber, "text":mytext]

NSNotificationCenter.defaultCenter().postNotificationName("refresh", object:myDict);

func refreshList(notification: NSNotification){
    let dict = notification.object as! NSDictionary
    let receivednumber = dict["number"]
    let receivedString = dict["mytext"]
}

Answer 2

Xcode中8.3.1•斯威夫特3.1

extension Notification.Name {
    static let refresh = Notification.Name("refresh")
}

---

let object: [String: Any] = ["id": 1, "email": "[email protected]"]
NotificationCenter.default.post(name: .refresh, object: object)

---

NotificationCenter.default.addObserver(self, selector: #selector(refreshList), name: .refresh, object: nil)

// Swift 4 or later note: add @objc to the selector `@objc func ...`
// don't forget  vvv add an underscore before the view controller method parameter 
func refreshList(_ notification: Notification) {
    if let object = notification.object as? [String: Any] {
        if let id = object["id"] as? Int {
            print(id)
        }
        if let email = object["email"] as? String {
            print(email)
        }
    }
}

Answer 3

您可以使用userInfo的Notification属性：

NotificationCenter.default.post(name: Notification.Name("refresh"),
                                object: nil,
                                userInfo: ["number":yourNumber, "string":yourString])

并检索：

func refreshList(notification: Notification){
    let receivednumber = notification.userInfo?["number"] as? Int ?? 0
    let receivedString = notification.userInfo?["string"] as? String ?? ""
}

Answer 4

其实有很多的方式来做到这一点。其中之一是通过像对象的数组：

let arrayObject : [AnyObject] = [mynumber,mytext]

NSNotificationCenter.defaultCenter().postNotificationName("refresh", object: arrayObject)

func refreshList(notification: NSNotification){

    let arrayObject =  notification.object as! [AnyObject]

    let receivednumber = arrayObject[0] as! Int
    let receivedString = arrayObject[1] as! String
}

Answer 5

雨燕4.0

首先创建一个字典多个值。

let name = "Abhi"
let age = 21
let email = "[email protected]"
let myDict = [ "name": name, "age":age, "email":email]
// post myDict
NotificationCenter.default.post(name: NSNotification.Name(rawValue: "post"), object: nil, userInfo: myDict)

加入观察者在其他的ViewController

NotificationCenter.default.addObserver(self, selector: #selector(doThisWhenNotify(notification:)), name: NSNotification.Name(rawValue: "post"), object: nil)

func doThisWhenNotify(notification : NSNotification) {
    let info = notification.userInfo
    print("name : ",info["name"])
    print("age : ",info["age"])
    print("email : ",info["email"])

}

Answer 6

雨燕4.0，我传递一个键：值，你可以添加多个键和值。

   NotificationCenter.default.post(name:NSNotification.Name(rawValue: "updateLocation"), object: ["location":"India"])

添加观察和方法的定义。您还需要删除的观察者。

NotificationCenter.default.addObserver(self, selector: #selector(getDataUpdate), name: NSNotification.Name(rawValue: "updateLocation"), object: nil)

@objc func getDataUpdate(notification: Notification) {
        guard let object = notification.object as? [String:Any] else {
            return
        }
        let location = object["location"] as? String
        self.btnCityName.setTitle(location, for: .normal)

        print(notification.description)
        print(notification.object ?? "")
        print(notification.userInfo ?? "")
    }