类型错误需要1个位置参数,但是给出了4个

问题描述 投票:0回答:1

我目前正在编写这个代码,用于执行涉及Matrix实现的作业:

class MyMatrix(object):
    def __init__(self, n, m, t):
        self.n = n
        self.m = m
        self.t = t

        self.data = []
        for i in range(0, self.n):
            row = []
            for i in range (0, self.m):
                row.append(self.t())
            self.data.append(row)

    def set(self, i, j, v):
        self.data[i][j] = v

    def get(self, i, j):
        self.data[i][j]

    def __str__(self):
        n = self.__class__.__name__ + "({})".format((self.n,self.m))
        for i in range(0, self.n):
            for j in range(0, self.m):
                s += str(self.get(i,j)) + " "
            s += "\n"
        return s

class MySparseMatrix(MyMatrix):

    def __init__(self):
        def __init__(self, n, m, t):
            self.n = n
            self.m = m
            self.t = t
            self.data = {}

    def set(self, i, j, v):
        key = (i, j)
        self.data[key] = v

    def get(self, i,j):
        key = (i, j)
        return self.data.get(key, self.t())

我正在尝试打印:

tt = MySparseMatrix(int, 2, 2)
tt.set(0,0,11)
tt.set(0,1,5)
tt.set(1,0,2)
print(tt.get(0,1))
print("tt = ", tt)

但它给了我

TypeError: __init__() takes 1 positional argument but 4 were given

有关如何解决此错误的任何建议?我是Python的新手。

(说我需要在我的问题中添加更多细节,所以请忽略这一点:dfjsdfasjdfasdjfasfajfkajsfkajsdfksakfjasdfkjasdfkasdfnasdfbafdbhsdfdfdfskfjdfjsfjsfsjafasjdfaskfgskadfakfaskdfaskfdalsfkasfdkalsdfkasldfksldfkasdfkasdflksdflakfdlkasdfkdddkasdfkafd)

python-3.x typeerror
1个回答
0
投票

这里的问题是__init__中的MySparseMatrix函数;在定义中有两个__init__函数,这意味着当你创建一个MySparseMatrix对象时,它不会调用接受参数的__init__函数。

要修复它,只需删除第一个__init__

def __init__(self, n, m, t):
    self.n = n
    self.m = m
    self.t = t
    self.data = {}
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