SQL - 查找没有匹配信用的发票

Question

简化表看起来像这样：

BillID|ProductID|CustomerID|Price|TypeID
------+---------+----------+-----+-------
111111|Product1 |Customer1 |  100| I
111112|Product1 |Customer1 | -100| C
111113|Product1 |Customer1 |  100| I
111114|Product1 |Customer1 | -100| C
111115|Product1 |Customer1 |  100| I

我需要找到具有匹配信用（C）但没有匹配信用（最后一条记录）的“奇数”发票的发票（I） - 或者相反（没有相应信用的无法匹配的发票）。

到目前为止，我有这个：

SELECT Invoices.billid, Credits.billid
FROM
    (SELECT B1.billid
    FROM billing B1
    WHERE B1.typeid='I') Invoices
INNER JOIN
    (SELECT B2.billid
    FROM billing B2
    WHERE B2.typeid='C') Credits
ON Invoices.customerid = Credits.customerid
    AND Invoices.productid = Credits.productid
    AND Invoices.price = -(Credits.price)

但它显然不起作用，因为它返回的东西如下：

billid | billid2
-------+ -------
111111 | 111112
111113 | 111114
111115 | 111114

我想得到的是一份无与伦比的发票清单;

billid |
-------+
111115 |

或者只选择匹配的发票;

billid | billid2
-------+ -------
111111 | 111112
111113 | 111114

发票号码（BillID）当然不一定是连续的，它只是一个简化的视图。

任何帮助，将不胜感激。

Answer 1

我很久以前写过这个，所以现在可能有更好的方法来解决它。我也试图让它适应你的桌面结构，所以如果它不是100％那么道歉。我还假设您的BillID按日期顺序是顺序的，即稍后输入更大的数字。我还假设发票总是积极的，信用票据总是负面的 - 所以我不打扰检查类型。

本质上，查询过滤掉任何匹配的项目。

无论如何这里是：

select *
from billing X
/* If we are inside the number of unmatched entries then show it. e.g. if there are 3 unmatched entries, and we are in the top 3 then display */
where (
  /* Number of later entries relating that match this account entry e.g. Price/Product/Customer */
  select count(*)
  from billing Z
  where Z.Customer = X.Customer and Z.ProductID = X.ProductID
  and Z.Price = X.Price
  and Z.BillID >= X.BillId
) <=
(
  /* Number of unmatched entries for this Price/Product/Customer there are, and whether they are negative or positive. */
  select abs(Y.Number)
  from (
    -- Works out how many unmatched billing entries for this Price/Product/Customer there are, and whether they are negative or positive
    select ProductID, CustomerID, abs(Price) Price, sum(case when Price < 0 then -1 else +1 end) Number
    from billing
    group by ProductID, CustomerID, abs(Price)
    having sum(Price) <> 0
  ) as Y
  where X.ProductID = Y.ProductID
  and X.CustomerID = Y.CustomerID
  and X.Price = case when Y.Number < 0 then -1*Y.Amount else Y.Amount end
)

Answer 2

这应该工作。我通过在信用卡之前添加几个连续发票进行测试。下面的查询显示所有具有匹配信用的发票，如果匹配不存在，则显示查询的别名“bar”部分的NULL。

SELECT * FROM (
  SELECT
    ROW_NUMBER() OVER(Partition By TypeID, CustomerID, ProductID, Price ORDER BY BillID ASC) AS rownumber,
    *
  FROM Billing
)  AS foo
LEFT JOIN 
  (SELECT
    ROW_NUMBER() OVER(Partition By TypeID, CustomerID, ProductID, Price ORDER BY BillID ASC) AS rownumber,
    *
  FROM Billing
) AS bar
on foo.CustomerID = bar.CustomerID and 
foo.ProductID = bar.ProductID and 
foo.rownumber = bar.rownumber and 
foo.Price = -1*bar.Price
where foo.Price > 1

这是我使用的更新数据：

以下是我的结果：

Answer 3

奇怪/偶数的事情让我有点担心。但假设这是一个增量键并且您的业务逻辑已到位，请尝试在WHERE子句，JOIN PREDICATE或实现Lead / Lag函数中包含此逻辑。

SELECT DISTINCT
 Invoices.billid
,Credits.billid

FROM
    (SELECT B1.billid
    FROM billing B1
    WHERE B1.typeid='I') Invoices
INNER JOIN (SELECT B2.billid
    FROM billing B2
    WHERE B2.typeid='C') Credits
ON Invoices.customerid = Credits.customerid
    AND Invoices.productid = Credits.productid
    AND Invoices.price = -(Credits.price)
    AND (Invoices.Billid + 1) = Credits.Billid

注意：这是使用您的INNER JOIN，因此我们将获得发票具有相应信用的情况。您也可以执行FULL OUTER JOIN，然后包含指定WHERE Invoices.Billid IS NULL OR Credits.Billid IS NULL的WHERE CLAUSE。这种情况会给你一个你没有匹配的尾随情况。