当我在 python 中使用多重处理时，主循环不起作用

Question

我正在用Python制作一个语音识别程序，我希望当我说“上面”时，它会连续运行循环以按下向下键，直到我再次不说上面，但现在在我包含线程来制作语音识别器连续运行，整个主循环不识别资源

from speech import *
import queue
import threading
import pyautogui
import keyboard
import time
import sys

def speech_func(res_queue):
    while True:
        res = speech()
        res_queue.put(res)

res_queue = queue.Queue()
prc=threading.Thread(target=speech_func, args=(res_queue,))
prc.start()

flower_active=False

while True:
    res = res_queue.get()
    
    if "above" in res:
        flower_active = not flower_active

    while flower_active:
        keyboard.press_and_release('down')
        time.sleep(0.1)

    if "after" in res:
        pyautogui.moveTo(1010,130)
        pyautogui.click()

    if "before" in res:
        pyautogui.moveTo(890,130)
        pyautogui.click()

    if "music" in res:
        pyautogui.moveTo(1680,130)
        pyautogui.click()
                         
    if "below" in res:
        keyboard.press_and_release('pageup')

    if "ending" in res:
        prc.join()
        sys.exit(0)

如果我删除线程，一切都会正常工作，除了向下箭头，当我说“上面”时，它将开始运行循环，但即使我再次说“上面”也不会停止

Answer 1

while flower_active:

正在阻止所有代码，因此无法从队列中获取下一个命令。它需要在单独的线程中运行

while flower_active:

。并且可能需要其他队列来停止循环并退出线程。

您也可以尝试使用

if

代替

while

然后

while True

会重复

while True:

    # ... code ...

    if flower_active:
        keyboard.press_and_release('down')
        time.sleep(0.1)

但是还有其他问题：

res_queue.get()

等待数据并且它会阻塞代码，并且可能需要在

if not res_queue.empty()

之前检查

.get()

while True:

    if not res_queue.empty():
        res = res_queue.get()
               
        if "above" in res:
            flower_active = not flower_active

        elif "after" in res:
            pyautogui.moveTo(1010,130)
            pyautogui.click()

        elif "before" in res:
            pyautogui.moveTo(890,130)
            pyautogui.click()

        elif "music" in res:
            pyautogui.moveTo(1680,130)
            pyautogui.click()
                             
        elif "below" in res:
            keyboard.press_and_release('pageup')

        elif "ending" in res:
            prc.join()
            sys.exit(0)
            
    # --- outside of `if not res_queue.empty():`
    
    if flower_active:
        keyboard.press_and_release('down')
        time.sleep(0.1)

我没有测试过。