var veg = {"mushroom": 30, "pepper": 60, "corn": 1, "carrot":
2, "pumpkin": 4}
如果对象值大于5,则从veg打印所有键。我似乎无法弄清楚如何将if语句条件放在我的代码中。
我通过对象使用for循环获得了所有的值和键。
function getKey(veg){
var arr = [];
for (var x of Object.keys(veg)){
arr.push(x);
}
return arr;
}
console.log(getKey(veg))
//----------------------------------------
function getVal(veg){
var arr = [];
for (var i of Object.values(veg)){
arr.push(i);
}
return arr;
}
console.log(getVal(veg))
// END GOAL
must return ["mushroom", "pepper"]
使用in的方法
var veg = {"mushrooms": 30, "peppers": 60, "meatballs": 1, "chicken":
2, "olives": 4}
function getKey(veg){
const arr = [],
obj = Object.keys(veg);
for (var x in obj){
if(veg[obj[x]] > 5){
arr.push(obj[x]);
}
}
return arr;
}
console.log(getKey(veg))
使用方法forEach
var veg = {"mushrooms": 30, "peppers": 60, "meatballs": 1, "chicken":
2, "olives": 4}
function getKey(veg){
const arr = [];
Object.keys(veg).forEach(function(item){
if(veg[item] > 5) arr.push(item);
});
return arr;
}
console.log(getKey(veg));
使用方法过滤器
var veg = {"mushrooms": 30, "peppers": 60, "meatballs": 1, "chicken":
2, "olives": 4}
function filterItems(arr) {
return Object.keys(arr).filter(function(el) {
return arr[el] > 5;
})
}
console.log(filterItems(veg));
var veg = {"mushrooms": 30, "peppers": 60, "meatballs": 1, "chicken":
2, "olives": 4}
function filterItems(arr) {
return Object.keys(arr).filter(el => arr[el] > 5);
}
console.log(filterItems(veg));
只需使用filter
和map
与Object.entries
:
var veg = {
"mushroom": 30,
"pepper": 60,
"corn": 1,
"carrot": 2,
"pumpkin": 4
};
var keys = Object.entries(veg).filter(([, v]) => v > 5).map(([k]) => k);
console.log(keys);
Object.getOwnPropertyNames将返回一个对象属性的数组,filter返回一个数组,其中传递给input函数的数组中的项返回true,在这种情况下大于5。
var veg = {"mushroom": 30, "pepper": 60, "corn": 1, "carrot": 2, "pumpkin": 4};
console.log(Object.getOwnPropertyNames(veg).filter(prop => veg[prop] > 5));
您应该使用for-in
循环迭代对象:
const veg = {"mushroom": 30, "pepper": 60, "corn": 1, "carrot": 2, "pumpkin": 4};
const out = [];
for (let key in veg) {
if (veg[key] > 5) out.push(key);
}
console.log(out);