从 php 7 更新到 php 8 后代码无法工作[已关闭]

Question

所以我多年来一直致力于这个托管游戏服务器的项目，这个按钮应该生成一个 ID 号并从文本框中获取值，然后将它们保存在 .json 数据库中。

最近我更新到 php 8，这个特定按钮在我的项目中停止工作。我希望有人可以帮助我修复它以与 php 8 一起使用。

编辑：我检查了日志和 PHP 致命错误：未捕获错误：未定义常量“Servers”是错误...在这一行： $idsList = array_column($data[Servers], 'serverID');

<?php if (isset($_POST['newServer'])) {
// retrieve user input
$serverName = (isset($_POST['serverName'])) ? $_POST['serverName'] : null;
$assignedPort = (isset($_POST['assignedPort'])) ? $_POST['assignedPort'] : null;
$userName = (isset($_POST['userName'])) ? $_POST['userName'] : null;
$passWord = (isset($_POST['passWord'])) ? $_POST['passWord'] : null;
$passWord = password_hash($passWord, PASSWORD_DEFAULT); // store a hash
// get .json file
$dataBase = "../../admin_files/database.json";
$data = json_decode(file_get_contents($dataBase), true);
$idsList = array_column($data[Servers], 'serverID');
$newID = max($idsList) + 1;
$formattedID = sprintf('%06d', $newID);

$data['Servers'][] = ['serverID' => $formattedID, 'gameTitle' => '7 Days To Die', 'serverName' => $_POST['serverName'], 'assignedPort' => $_POST['assignedPort'], 'commandLine' => ''];
// insert new user credentials
$data['Users'][] = ['userName' => $userName, 'passWord' => $passWord];

// write  to flat file database
file_put_contents($dataBase, json_encode($data, JSON_UNESCAPED_SLASHES | JSON_PRETTY_PRINT | LOCK_EX));
    mkdir($formattedID);

header('Location: ' . 'servers.php'); }?>

我尝试将 php 回滚到 php 7，它再次工作，但我需要它与 php 8 一起使用。

Answer 1

提供的代码片段似乎使用 PHP 7 的隐式类型转换，该类型在 PHP 8 中已弃用，并且可能会导致严格类型声明的问题。为了使代码与 PHP 8 兼容，您需要将变量显式转换为其各自的数据类型。这是修改后的代码：

<?php
if (isset($_POST['newServer'])) {
    // Retrieve user input and explicitly cast to their respective data types
    $serverName = (isset($_POST['serverName'])) ? (string) $_POST['serverName'] : null;
    $assignedPort = (isset($_POST['assignedPort'])) ? (integer) $_POST['assignedPort'] : null;
    $userName = (isset($_POST['userName'])) ? (string) $_POST['userName'] : null;
    $passWord = (isset($_POST['passWord'])) ? (string) $_POST['passWord'] : null;

    // Hash the password securely
    $passWord = password_hash($passWord, PASSWORD_DEFAULT);

    // Retrieve and process the JSON database
    $dataBase = "../../admin_files/database.json";
    $data = json_decode(file_get_contents($dataBase), true);

    // Generate a new server ID
    $idsList = array_column($data['Servers'], 'serverID');
    $newID = max($idsList) + 1;
    $formattedID = sprintf('%06d', $newID);

    // Add new server and user credentials to the JSON data
    $data['Servers'][] = [
        'serverID' => $formattedID,
        'gameTitle' => '7 Days To Die',
        'serverName' => $serverName,
        'assignedPort' => $assignedPort,
        'commandLine' => ''
    ];
    $data['Users'][] = [
        'userName' => $userName,
        'passWord' => $passWord
    ];

    // Update the JSON file
    file_put_contents($dataBase, json_encode($data, JSON_UNESCAPED_SLASHES | JSON_PRETTY_PRINT | LOCK_EX));

    // Create a directory for the new server
    mkdir($formattedID);

    // Redirect to the servers page
    header('Location: ' . 'servers.php');
}

通过将变量显式转换为其各自的数据类型，您将确保与 PHP 8 严格类型强制的兼容性，并防止隐式类型转换引起的任何潜在问题。