如何使用带日期的plotly graph_objects散点图

问题描述 投票:0回答:1

从我复制到我自己的服务器的已知公共数据集开始。

数据集在这里:https://www.kaggle.com/imdevskp/corona-virus-report/download

import pandas as pd
#df = pd.read_csv("http://g0mesp1res.dynip.sapo.pt/covid_19_clean_complete.csv", index_col=4, parse_dates=True)
df = pd.read_csv("http://g0mesp1res.dynip.sapo.pt/covid_19_clean_complete.csv")
df=df.drop(labels=None, axis=0, index=None, columns=['Province','Lat','Long'], level=None, inplace=False, errors='raise')
#print(df.head())
df['Date']=pd.to_datetime(df['Date'])
#print(df.head())
list_countries = ['Portugal','Brazil','Spain','Italy','Korea, South','Japan']
df= df[df['Country'].isin(list_countries)]
df_pt = df[df.Country == 'Portugal']
df_es = df[df.Country == 'Spain']
df_it = df[df.Country == 'Italy']
print(df_pt.head())
print(df_pt.tail())

我得到了我的期望

       Country       Date  Confirmed  Deaths  Recovered
59    Portugal 2020-01-22          0       0          0
345   Portugal 2020-01-23          0       0          0
631   Portugal 2020-01-24          0       0          0
917   Portugal 2020-01-25          0       0          0
1203  Portugal 2020-01-26          0       0          0
        Country       Date  Confirmed  Deaths  Recovered
15503  Portugal 2020-03-16        331       0          3
15789  Portugal 2020-03-17        448       1          3
16075  Portugal 2020-03-18        448       2          3
16361  Portugal 2020-03-19        785       3          3
16647  Portugal 2020-03-20       1020       6          5

但是,绘制时,似乎所有数据都在一月份!

import plotly.graph_objects as go
fig = go.Figure( go.Scatter(x=df.Date, y=df_pt.Confirmed, name='Portugal'))
fig.show()

绘制输出图:

enter image description here

缺少什么?

plotly timeserieschart
1个回答
0
投票
更改x轴:

import plotly.graph_objects as go fig = go.Figure(go.Scatter(x=df_pt.Date, y=df_pt.Confirmed, name='Portugal')) fig.show()

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