计算分组依据，并添加禁用类别

Question

我有一个Automate的表，定义如下：

Colonne Type
id          int(11) Incrément automatique   
name        varchar(255)    
type        varchar(255)    
code        varchar(255)    
password    varchar(255)    
active      tinyint(1)

我为仪表板制作这样的视图：

SELECT COUNT('type') as count, type as name
FROM automate
GROUP BY type;

但是如果激活了自动功能，这并不重要...首先，我想从报告中删除未激活的自动化（添加简单的where activated = 1即可轻松实现）

但是我如何添加伪造的type来计数未激活的自动化？

实际结果：

| type   | count |
| comx   |     4 |
| gateway|     3 |

想要的结果：

| type        | count |
| comx        |     1 |
| gateway     |     2 |
| unactivated |     4 |

（假设type来自一个枚举，并且在bdd中不能有unactivated值]

Answer 1

考虑使用条件聚合：

select
    type,
    count(*) cnt,
    sum(case when active = 1 then 1 else 0 end) activated,
    sum(case when active = 0 then 1 else 0 end) inactivated
from automate
group by type

对于每种类型，查询将为您提供记录总数，active = 1处的记录数和active = 0处的记录数。

Answer 2

如果active只能取0和1的值，则可以使用：

SELECT type, SUM(active) as num_active,
       SUM(1 - active) as num_inactive
FROM automate
GROUP BY type;

如果要将它们添加为其他行，则：

SELECT type, COUNT(*) as num_active,
       SUM(1 - active) as num_inactive
FROM automate
WHERE active = 1
GROUP BY type
UNION ALL
SELECT 'inactive', COUNT(*)
FROM automate
WHERE active = 0;