如何按预期聚合JSON数据？

Question

我有来自 API 的响应文本，如下所示，我想将它们聚合为新格式响应。但这是相当困难的，请帮助我（使用JavaScript）

API 的响应:

[
  {
    sumTime: "2024-04-25 12:00:00",
    equipParaName: "P1",
    sumValue: 5
  },
  {
    sumTime: "2024-04-25 05:00:00",
    equipParaName: "P2",
    sumValue: 10,
  },
  {
    sumTime: "2024-04-25 09:00:00",
    equipParaName: "P1",
    sumValue: 8
  },
  {
    sumTime: "2024-04-25 08:00:00",
    equipParaName: "P2",
    sumValue: 3,
  },
  {
    sumTime: "2024-04-25 08:00:00",
    equipParaName: "P3",
    sumValue: 12,
  }
]

条件：

• 相同

  sumTime

  ，

  equipParaName

  不可重复

• 如果有3个唯一的

  equipParaName

  ，则预期结果在一个对象中最多有3个属于它们的属性

结果列表中的

• 相同

  equipParaName

  必须按

  sumTime

  ASC
  排序

  equipParaName: P1, sumTime: 2024-04-25 12:00:00, sumValue: 5
  equipParaName: P1, sumTime: 2024-04-25 09:00:00, sumValue: 8
  ==> The sumTime 2024-04-25 09:00:00 should be added to 1st object and sumTime: 2024-04-25 12:00:00 added to 2nd object in result list
  

期待：

[
  {
    index: 1,
    P1: 8,
    P1_sumTime: "2024-04-25 09:00:00",
    P2: 10,
    P2_sumTime: "2024-04-25 05:00:00",
    P3: 12,
    P3_sumTime: "2024-04-25 07:00:00"
  },
  {
    index: 2,
    P1: 5,
    P1_sumTime: "2024-04-25 12:00:00",
    P2: 3,
    P2_sumTime: "2024-04-25 08:00:00"
  }
]

Answer 1

第一个暴力方法：

1. 仅按

   equipParaName

    对相同 

   sumTime
项目进行排序
2. 将项目收集到子数组中，以便子数组仅包含唯一的

   equipParaName

3. 映射到您想要的格式

const input=[{sumTime:"2024-04-25 12:00:00",equipParaName:"P1",sumValue:5},{sumTime:"2024-04-25 05:00:00",equipParaName:"P2",sumValue:10},{sumTime:"2024-04-25 09:00:00",equipParaName:"P1",sumValue:8},{sumTime:"2024-04-25 08:00:00",equipParaName:"P2",sumValue:3},{sumTime:"2024-04-25 08:00:00",equipParaName:"P3",sumValue:12}];

const ps = {};
for(let i=0;i<input.length;i++){
  const item = input[i];
  (ps[item.equipParaName] ??= []).push(i);
}

const sorted = [];
for(const [p, grp] of Object.entries(ps)){
  const orig = grp.slice();
  const idxs = grp.sort((a,b) => (a = input[a], b = input[b], a.sumTime > b.sumTime ? 1 : a.sumTime < b.sumTime ? -1 : 0));
  for(let i=0;i<orig.length;i++){
    sorted[orig[i]] = input[idxs[i]];
  }
}

const slots = [];
for(const item of sorted){
  const slot = slots.find(slot => !slot[item.equipParaName]);
  if(slot) slot[item.equipParaName] = item;
  else slots.push({[item.equipParaName]: item});
}

const result = slots.map((grp, i) => Object.entries(grp).reduce((r, [key, {sumValue, sumTime}]) => (r[key] = sumValue, r[key + '_sumTime'] = sumTime, r), {index:i+1}));

console.log(result);

.as-console-wrapper{
max-height:100% !important;
}