在 Laravel 中使用 SQL ROW_NUMBER 应用雄辩的热切限制查询

Question

正如 @JonasStaudenmeir 在 laravel eager loading with limit 上的回答，该查询如下所示：

User::select('id')
    ->with([
        'posts' => fn($query) => $query->select(['id', 'user_id'])->limit(4)
    ])
    ->limit(2)
->get();

select `id` from `users` limit 2

select * from (select `id`, `user_id`, row_number() over (partition by `posts`.`user_id`) as laravel_row from `posts` where `posts`.`user_id` in (1, 3)) as laravel_table where laravel_row <= 4 order by laravel_row

现在，我的兴趣是手动完成，这就是我在这里尝试的：

User::select('id')
->with([
    'posts' => fn($query) => $query->select(['id', 'user_id'])
        ->selectRaw("row_number() over (partition by `posts`.`user_id`) as laravel_row")
        ->where('laravel_row', '<=', 4)
        ->orderBy('laravel_row')
])
->limit(2)
->get();

另外，我从网上获得了一些帮助（SQLtoEloquent），但语法格式不正确，所以也失败了。

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'laravel_row' in 'where clause'

select `id`, `user_id`, row_number() over (partition by `posts`.`user_id`) as laravel_row from `posts` where `posts`.`user_id` in (1, 3) and `laravel_row` <= 4 order by `laravel_row` asc

更新：

按照@Igor的建议，我尝试使其与包类似并且更方便，但与预期的输出不匹配。

应用\提供商\AppServiceProvider.php

public function boot(): void
{
    \Illuminate\Database\Eloquent\Relations\Relation::macro('limit', function(int $value) {

        if($this->parent->exists) {

           $this->query->limit($value);

        } elseif ($value >= 0) {

            // When I tried on the Model(User), it succeeded the below logic
            // 2 was expected because the total number of users fetched is 2 but it didn't happen
            $parentLimitValue = $this->query->getQuery()->limit; // null

            // $parentLimitValue = $this->parent->getQuery()->limit; // null
            // $parentLimitValue = $this->related->getQuery()->limit; // null

            $parentLimitValue ??= 1;

            $this->query
                ->selectRaw("row_number() over (partition by ".$this->getExistenceCompareKey().") as laravel_row")
                ->orderBy('laravel_row')
            ->limit($value * ($parentLimitValue ?: 1));
        }
        return $this;
    });
}

有谁知道我应该把眼睛放在哪里才能最小化这个包裹？

Answer 1

我认为你需要删除 where 并将 limit 添加到子查询中

User::select('id')
->with([
    'posts' => fn($query) => $query->select(['id', 'user_id'])
        ->selectRaw("row_number() over (partition by `posts`.`user_id`) as laravel_row")
        ->orderBy('laravel_row')
        ->limit(4) 
])
->limit(2)
->get();

更新

要限制用户和每个用户的帖子，请使用以下命令：

$usersCount = 2;
$postsPerUser = 4;
$users = User::select('id')
->with([
    'posts' => fn($query) => $query->select(['id', 'user_id'])
        ->selectRaw("row_number() over (partition by `posts`.`user_id`) as laravel_row")
        ->limit($usersCount * $postsPerUser) 
        ->orderBy('laravel_row')
])
->limit($usersCount)
->get();

Answer 2

根据 @Igor 的回复，我将其放入 traits 和 local 范围中，使其更加方便。

应用\Traits\WithEagerLimit.php

<?php

namespace App\Traits;

use Illuminate\Database\Eloquent\Builder;

trait WithEagerLimit
{
    public function scopeWithEagerLimit(Builder $builder, string $relation, callable $callback)
    {
        return $builder->with([ $relation => function($query) use ($builder, $callback) {

            $limit = $builder->getQuery()->limit ?: 1;

            // Illuminate\Database\Eloquent\Relations\Relation
            $query = call_user_func_array($callback, [$query]);

            // Illuminate\Database\Query\Builder
            $dbQB = $query->getQuery()->getQuery();

            if(!$dbQB->limit) {
                return $query;
            }

            $dbQB->limit *=  $limit;

            return $query->when(is_null($dbQB->columns), fn($q) => $q->select('*'))
                ->selectRaw("row_number() over (partition by ".$query->getExistenceCompareKey().") as laravel_row")
                ->orderBy('laravel_row');
        }]);
    }
}

在相应模型上使用

WithEagerLimit

特征。

例如：

class User extends Model {

    use \App\Traits\WithEagerLimit;
    
    //...

    public function posts()
    {
        return $this->hasMany(Post::class);
    }
}

现在，您可以通过执行以下操作将

withEagerLimit()

链接到任何查询：

简单的预加载功能

User::withEagerLimit('posts', fn($query) => $query)->get();

// SQL
select * from `users`

select * from `posts` where `posts`.`user_id` in (1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

急切加载功能的条件

User::query()
    ->withEagerLimit('posts', fn($query) => $query->select(['id', 'user_id'])->where('id', '<=', 5))
->get();

// SQL
select * from `users`

select `id`, `user_id` from `posts` where `posts`.`user_id` in (1, 2, 3, 4, 5, 6, 7, 8, 9, 10) and `id` <= 5

关于预加载功能的复杂 SQL RAW 查询

User::query()
    ->select('id')
    ->withEagerLimit('posts',
        fn($query) => $query->select(['id', 'user_id'])
            ->whereRaw('MOD(id, 2) = 0')
            ->limit(4)
    )
    ->whereRaw('MOD(id, 2) = 1')
    ->skip(3)
    ->take(2)
    ->latest('id')
->get();

// SQL
select `id` from `users` where MOD(id, 2) = 1 order by `id` desc limit 2 offset 3

select `id`, `user_id`, row_number() over (partition by posts.user_id) as laravel_row from `posts` where `posts`.`user_id` in (1, 3) and MOD(id, 2) = 0 order by `laravel_row` asc limit 8

预加载功能的分页

User::query()
    ->withEagerLimit('posts', fn($query) => $query->limit(4))
->paginate(5);

// SQL
select count(*) as aggregate from `users`

select * from `users` limit 5 offset 0

select *, row_number() over (partition by posts.user_id) as laravel_row from `posts` where `posts`.`user_id` in (1, 2, 3, 4, 5) order by `laravel_row` asc limit 20

对于那些急切等待答案的人

您应该在主查询和子查询中与

->limit($value)

链接的任何查询中调用

take()

或等效方法（即

skip()

、

paginate()

、

->withEagerLimit($relationName, $callback)

或类似过程）。

User::query()
    ->select('id')
    ->withEagerLimit('posts', fn($query) => $query->select(['id', 'user_id'])->limit(4))
    ->limit(2)
->get();