无法使用 GuzzleHttp 发布：错误：标头值必须为标量或 null，但提供了数组

Question

我尝试使用

GuzzleHttp

发布以下 html 表单，但由于在标题中设置

form_params

时出现错误，我无法这样做。

InvalidArgumentException: Header value must be scalar or null but array provided.

<form action="https://example.com/process" method="post">
 <input type="hidden" name="data" value="<?php echo $base64_encrypted_json; ?>”>
<?php foreach($items_encoded as $item) { ?>
 <input type="hidden" name="item_data[]" value="<?php echo $item; ?>”>
<?php } ?>
 <input type="hidden" name="rid" value="example">
 <input type="submit">
</form>

这是我在构造函数中的代码。

        $this->setRequest(
            new Request(
                "POST",
                $this->getConfig()->get(Module::MODULE_ENDPOINT_URL)["submit"]
            )
        );

        /** @var array $submitDataArray */
        $submitDataArray = $this->getConfig()->get(Module::MODULE_SUBMIT_REQUEST_DATA_CONFIG)->toArray();
        $submitDataArray["data"] = json_encode($submitDataArray["data"]);

        /** @var array $splitItemsData */
        $splitItemsData = str_split(json_encode($submitDataArray["itemData"], true), 800);
        /** @var array $itemDataEncoded */
        $itemDataEncoded = [];
        foreach ($splitItemsData as $itemDataString) {
            $itemDataEncoded[] = json_encode($itemDataString);
        }
        $submitDataArray["itemData"] = $itemDataEncoded;
        $submitDataModel = (new SubmitDataModel())->exchangeArray($submitDataArray);
        $this->setSubmitDataModel($submitDataModel);

这是我的

init()

方法。

    public function init(): void
    {
        /** @var array $submitDataModel */
        $submitDataModel = $this->getSubmitDataModel()->exchangeArray();

        /** @var array $formParams */
        $formParams = array();
        $formParams["rid"] = $submitDataModel["rid"];
        $formParams["data"] = $submitDataModel["data"];
        $formParams["item_data"] = $submitDataModel["itemData"];

        $this->getRequest()->withHeader("Content-Type", "application/x-www-form-urlencoded");
        $this->getRequest()->withHeader("form_params", $formParams);
    }

$submitDataArray

如下

rid = "sandbox"
data = "{"username":"sandbox","request_data":{"return_urls":{"abort":"https:\/\/example.com\/checkout\/abort","fail":"https:\/\/example.com\/checkout\/rejected","success":"https:\/\/example.com\/checkout\/success","return_data":"https:\/\/example.com\/c832jdafs94kb"},"request_type":"standard_finance_request","test_mode":1,"order_details":{"order_id":"","currency":"GBP"},"customer_details":{"firstnames":"","surname":"","email":"","phone":"","address":"","city":"","country":"","postcode":"","dob":"","delivery_address":"","delivery_city":"","delivery_postcode":"","delivery_country":"UK"}}}"
itemData = {array} [1]
 0 = ""[{\"description\":\"\",\"quantity\":0,\"price\":0}]""

为了保持简洁，我跳过了一些不必要的细节。

更新： 我也尝试过

multipart

来处理数组，但仍然没有帮助。

        $this->getRequest()->withHeader("Content-Type", "multipart/form-data");
        $this->getRequest()->withHeader("multipart", $formParams);

Answer 1

感谢@ITgoldman 的领导。我重构了部分代码，如下所示，它对我有用。

        $this->getRequest()->withHeader("Content-Type", "application/x-www-form-urlencoded");
        $this->getRequest()->withBody(\GuzzleHttp\Psr7\Utils::Streamfor(http_build_query($formParams)));

这就是它的工作原理。

http_build_query()

函数将数组转换为查询字符串，然后可以使用

\Psr\Http\Message\StreamInterface

方法将其转换为

\GuzzleHttp\Psr7\Utils::Streamfor()

，以便与

withBody()

方法一起使用。