如何使用jquery在html Dom中打印json值？

Question

如何在html dom中打印json数据？

我有电影json，我附加选择标签，我想在选择电影时将电影名称附加到锚标签...

下面是我的HTML

<div class="UserData">
            <h1><a href="moviebooking.html">MyMovie-Ticket-Booking</a></h1>
            <select class="selectCity" id="selectCity">
                <option value="City">Select City</option>
                <option value="Bengaluru">Bengaluru</option>
                <option value="Hyderabad">Hyderabad</option>
                <option value="Guntur">Guntur</option>
                <option value="Ongole">Ongole</option>
            </select>
            <span id="welcome"> </span>
        </div>

以下是js

$(document).ready(function() {
  var cityData = [{
      cityName: 'Bengaluru',
      value: "Bengaluru",
      data: [{
          movieName: 'ABC',
          theaterName: 'Tulsi Theatre'
        },
        {
          movieName: 'DEF',
          theaterName: 'PVR'
        },
        {
          movieName: 'GHI',
          theaterName: 'Srinivasa Theatre'
        }
      ]
    },


    {
      cityName: 'Hyderabad',
      value: "Hyderabad",
      data: [{
          movieName: '123',
          theaterName: 'Theatre1'
        },
        {
          movieName: '456',
          theaterName: 'PVR2'
        },
        {
          movieName: '789',
          theaterName: 'Theatre3'
        }
      ]
    },

    {
      cityName: 'Guntur',
      value: "Guntur",
      data: [{
          movieName: 'ABC1',
          theaterName: 'Theatre4'
        },
        {
          movieName: 'DEF2',
          theaterName: 'PVR3'
        },
        {
          movieName: 'GHI3',
          theaterName: 'Theatre5'
        }
      ]
    },

    {
      cityName: 'Ongole',
      value: "Ongole",
      data: 'currently not available'
    }
  ];
    $("#selectCity").on('change', function() {
    var locations = cityData.filter(c => c.cityName === $(this).val())[0].data;
    var locationString = '';
    var locationString2 = '';
    console.log(locations)
    $.each(locations, function(i, item) {

        console.log(JSON.stringify(item));
        locationString += '<option value="' + item.theaterName + '">' + item.theaterName + '</option>';
        locationString2 += '<option value="' + item.movieName + '">' + item.movieName + '</option>';
    });
    $('#secondselectbox').html(locationString);
    $('#thirdselectbox').html(locationString2);
});

});

如何在选择标签中选择电影名称后附加剧院名称和电影名称....

以及如何分别过滤电影和戏剧......

Answer 1

你的html中没有select和#secondselectbox和#thirdselectbox。你仍然试图把html放在那些。在你的html中添加两个带有这些id的select。

$(document).ready(function() {
  var cityData = [{
      cityName: 'Bengaluru',
      value: "Bengaluru",
      data: [{
          movieName: 'ABC',
          theaterName: 'Tulsi Theatre'
        },
        {
          movieName: 'DEF',
          theaterName: 'PVR'
        },
        {
          movieName: 'GHI',
          theaterName: 'Srinivasa Theatre'
        }
      ]
    },


    {
      cityName: 'Hyderabad',
      value: "Hyderabad",
      data: [{
          movieName: '123',
          theaterName: 'Theatre1'
        },
        {
          movieName: '456',
          theaterName: 'PVR2'
        },
        {
          movieName: '789',
          theaterName: 'Theatre3'
        }
      ]
    },

    {
      cityName: 'Guntur',
      value: "Guntur",
      data: [{
          movieName: 'ABC1',
          theaterName: 'Theatre4'
        },
        {
          movieName: 'DEF2',
          theaterName: 'PVR3'
        },
        {
          movieName: 'GHI3',
          theaterName: 'Theatre5'
        }
      ]
    },

    {
      cityName: 'Ongole',
      value: "Ongole",
      data: []
    }
  ];
    $("#selectCity").on('change', function() {
    var locations = cityData.filter(c => c.cityName === $(this).val())[0].data;
    var locationString = '';
    var locationString2 = '';
    $.each(locations, function(i, item) {
        locationString += '<option value="' + item.theaterName + '">' + item.theaterName + '</option>';
        locationString2 += '<option value="' + item.movieName + '">' + item.movieName + '</option>';
    });
    $('#secondselectbox').html(locationString);
    $('#thirdselectbox').html(locationString2);
});
  $("#thirdselectbox").on("change", function(){
    $("span#selectedMovie").text($(this).val());
  });
  $("#secondselectbox").on("change", function(){
    $("span#selectedTheater").text($(this).val());
  });

  $('#theaterButton').click(function(){
    var arrTheater = [];
    cityData.forEach(function(theater, i){
      var allTheaters = theater.data.map(t => t.theaterName);
      arrTheater = arrTheater.concat(allTheaters);
    });
    $('#container').html('<b>Theaters: </b><br/>' + arrTheater.join(', '));
  });
  
  $('#movieButton').click(function(){
    var arrMovie = [];
    cityData.forEach(function(movie, i){
      var allMovies = movie.data.map(m => m.movieName);
      arrMovie = arrMovie.concat(allMovies);
    });
    $('#container').html('<b>Movies: </b><br/>'+ arrMovie.join(', '))
  });
  
  
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="UserData">
    <h1><a href="moviebooking.html">MyMovie-Ticket-Booking</a></h1>
    <select class="selectCity" id="selectCity">
        <option value="City">Select City</option>
        <option value="Bengaluru">Bengaluru</option>
        <option value="Hyderabad">Hyderabad</option>
        <option value="Guntur">Guntur</option>
        <option value="Ongole">Ongole</option>
    </select>
    <span id="welcome"> </span>
    <select class="selectTheater" id="secondselectbox">
    </select>
    <select class="selectMovie" id="thirdselectbox">
    </select>
</div>
<fieldset style="margin-top:20px;">
  <legend>Your Selection</legend>
  <div>Theater: <span id="selectedTheater"></span></div>
  <div>Movie: <span id="selectedMovie"></span></div>
</fieldset>
<div  style="margin-top:20px;">
  <input type="button" id="theaterButton" value="Get Theater"/>
  <input type="button" id="movieButton" value="Get Movie"/>
  <div id="container"></div>
</div>