我正在尝试创建扫雷游戏。为了表明在该位置已放置一个标志，我想在该插槽中放置一个4。我不太确定如何更新数组的1个元素，我在网上发现的所有信息都遍历整个数组并更改了值。反正有这样做吗？我遇到麻烦的特定行是：
(*arr)[tempH][tempV] = 4;
其余部分在这里。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <time.h>
int * arr;
void initialization(int vf, int hf) {
printf("%s\n", "Setting up the game");
int i, j, count = 0; // fills the board with a random sequence of 1's and 0's
for (i = 0; i < hf; i++) //representing bombs and empty spaces
for (j = 0; j < vf; j++)
*
(arr + i * vf + j) = (rand() % 2);
//0 is nothing 1 is bombs
for (i = 0; i < hf; i++) {
for (j = 0; j < vf; j++) {
printf("%d ", *(arr + i * vf + j));
if (j == hf - 1) {
printf("\n"); //creates new line at the end of row
}
}
}
printf("%s\n", "1 contains a bomb, 0 does not."); //game setup
}
void teardown() {
printf("%s\n", "Destroying the game"); //game destroy
}
void input(char select, char * command, int * coord_h, int * coord_v, int * stop) {
const int tempH = * coord_h; //creates temporary holders for coords
const int tempV = * coord_v;
printf("%s\n", "[F]Flag ");
printf("%s\n", "[R]Remove Flag ");
printf("%s\n", "[A] Assert a spot is mine free ");
printf("%s\n", "[Q] Quit");
scanf(" %c", & select);
if (select == 'f') {
printf("Please enter a horizontal coordinate: "); //selects a coordinate
scanf(" %d", coord_h);
printf("Please enter a vertical coordinate: "); //selects a coordinate
scanf(" %d", coord_v); &
(*arr)[tempH][tempV] = 4;
//TODO: REST OF LETTERS
} else if (select == 'r') {
} else if (select == 'a') {
printf("Please enter a horizontal coordinate: "); //selects a coordinate
scanf(" %d", coord_h);
printf("Please enter a vertical coordinate: "); //selects a coordinate
scanf(" %d", coord_v);
} else if (select == 'q') {
* stop = 1; //Stops loop in main
} else {
}
}
void update(int * coord_h, int * coord_v, int * type, int ** ptr, int hf, int vf) {
const int tempH = * coord_h; //creates temporary holders for coords
const int tempV = * coord_v;
printf("%d\n", ptr[tempH][tempV]); //testing values
if (ptr[tempH][tempV] == 1) { //checks to see if array at that point is a bomb
* type = 1; //returns type for display (bomb)
} else {
* type = 0; //returns type for display(not bomb)
}
int i, j, count = 0; // fills the board with a random sequence of 1's and 0's
for (i = 0; i < vf; i++) { //representing bombs and empty spaces
//memcpy(&updateArr[i], &arr[i], sizeof(int));
}
for (i = 0; i < hf; i++) {
for (j = 0; j < vf; j++) {
printf("%d ", *(arr + i * vf + j));
if (j == hf - 1) {
printf("\n"); //creates new line at the end of row
}
}
}
}
void display(int * type, int ** ptr, int hf, int vf) {
if ( * type == 1) { //takes type from update and displays
printf("%s\n", "BOOM");
} else if ( * type == 0) {
printf("%s\n", "OK");
}
}
int main() {
srand(time(NULL)); //creates random seed for bomb placement
int * stop = 0;
char select;
int * displayType;
char command[100];
int v, h; //board sizing
int coord_h, coord_v; //user inputed coords
printf("%s\n", "Enter horizontal board length: ");
scanf("%d", & h);
printf("%s\n", "Enter vertical board length:");
scanf("%d", & v);
const int vf = v,
hf = h; //sets constants for board so the array can use them
arr = (int * ) malloc(hf * vf * sizeof(int)); //dynamic memory allocation for board 2d array
int ** ptr = & arr;
initialization(vf, hf);
while (stop == 0) {
input(select, command, & coord_h, & coord_v, stop);
update( & coord_h, & coord_v, displayType, ptr, hf, vf);
display(displayType, ptr, hf, vf);
}
teardown();
}
问题是您将arr初始化为1D数组，并且希望像2D一样对其进行访问。基本上，arr只是指向在内存中连续的hf * vf int变量的第一个索引的指针。如果要使用实际的2D数组，则需要将arr更改为指向指针（int **）的指针，然后可以像arr[i][j]一样访问它。另外，您可以像这样保持它（一维数组），并实现一个将arr，i，j和新值作为参数然后更新*(arr + i * vf + j)的函数。