我有一个包含数值和NaN的单元格矩阵。如何删除NaN值并“修剪”我的矩阵。
例如,我有以下矩阵:
A = { 1, 12, NaN; 1 ,4, NaN; 1 , 2 , NaN ; NaN, NaN, NaN; 1, 2, NaN };
我想删除NaN并调整矩阵大小以获得此矩阵。可以没有循环吗? (使用矢量化)
A = [ 1, 12; 1, 4; 1, 2; 1, 2];
A = { 1, 12, NaN; 1 ,4, NaN; 1 , 2 , NaN ; NaN, NaN, NaN; 1, 2, NaN };
A = cell2mat(A) ; % convert the given cell to matrix
[m,n] = size(A) ; % get size of the matrix
A(sum(isnan(A),2)==n,:) = [] ; % remove rows with all NaN's in a row
[m,n] = size(A) ; % get updated size of A
A(:,sum(isnan(A),1)==m) = [] ; % remove columns with all NaN's in a column
结果
A = [1 12
1 4
1 2
1 2]
乍一看,我没有看到(自动)保留矩阵的“形状”(尺寸)的方法。对于转换和提取,有一个简单的解决方案:
B = cell2mat(A)
B =
1 12 NaN
1 4 NaN
1 2 NaN
NaN NaN NaN
1 2 NaN
B = B(~isnan(B))
B =
1
1
1
1
12
4
2
2
我将进一步考虑(自动)调整大小。